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zubka84 [21]
3 years ago
11

Are there infinitely many primes p such that p − 1 is a perfect square? In other words: Are there infinitely many primes of the

form n2 + 1?
Mathematics
1 answer:
Vilka [71]3 years ago
4 0
I wish I had an answer for you! Unfortunately, this one has stumped even professional mathematicians for over a century. It was first presented by mathematician Edmund Landau in 1912, and it’s gone unproven ever since. I can’t give you a solution, but I can definitely say you should submit your findings to a mathematical journal if you ever find one!
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State if each triangle is a right triangle: *<br><br>13 in<br>2 in<br>12 in<br>​
olga_2 [115]

Answer:

It would be a obtuse triangle instead

Step-by-step explanation:

By using pythagorean and theorem (a^2 + b^2 = c^2)

So it would be 13^2___2^2 + 12^2

When you square them, you get 169___4 + 144

144 + 4 = 148, which is less than 169

SO it would be 169>148

So no, not a right triangle

7 0
3 years ago
Find the slope<br><br> -3/5<br><br> 3/5<br><br> 5/3<br><br> -5/3
Monica [59]
The slope is y=-5/3x+2
8 0
2 years ago
the table shows the highest of four students arrange the students in order from shortest to tallest Kim 56.03 + x + 56.3 + 56.14
saul85 [17]
56.03 56.14 56.3 57.1
6 0
3 years ago
4.) Find the quotient<br><br> 20 ÷ 1/4<br><br><br> A.) 5<br> B.) 40<br> C.) 10<br> D.) 80
Mazyrski [523]

1/4 of 20 is 5

A is the answer

7 0
3 years ago
3 exponet 8×4+9÷1×56+57
nika2105 [10]
You would use PEMDAS

But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57

Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57

Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57

Now you can add all of the numbers together
32➕504=536
536➕57=593

Your answer is 593

Hope this helps! :3
4 0
3 years ago
Read 2 more answers
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