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Fed [463]
3 years ago
15

What is 3730 watts expressed as horsepower? 5 30 10 20

Physics
2 answers:
pishuonlain [190]3 years ago
7 0

Hello.

The answer is: 5

To get the answer you divide it out by how many watts are in a HP.

So divide 3730 * 745.7=5

have a nice day

gizmo_the_mogwai [7]3 years ago
4 0

Answer:

5

Explanation:

Power is the amount of energy consumed per unit time. Watts and horsepower are units of power.

P = \frac{E}{t}

1 horsepower = 746 watts

⇒1 watt = 0.00134 hp

3730 watts would be equivalent to:

3730 × 0.00134 hp = 5 hp

Thus, 3730 watts can be expressed as 5 horsepower.

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1. Kinetic

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What does m/s/s mean?
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Explanation:

There are two answers

m/(s/s)=m

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3 years ago
Which is a feature of a cladogram?BY MOHAMED<br><br> I GIVEING A !)) 100 point RIGHT NOW ASP
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Constructed cladograms all typically share certain key features: Root – The initial ancestor common to all organisms within the cladogram (incoming line shows it originates from a larger clade) Nodes – Each node corresponds to a hypothetical common ancestor that speciated to give rise to two (or more) daughter taxa.

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6 0
3 years ago
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9. Una jeringa contiene cloro gaseoso, que ocupa un volumen de 95 mL a una presión de 0,96 atm. ¿Qué presión debemos ejercer en
masha68 [24]

Answer:

2.61 atm

Ley de Boyle

Explanation:

P_1 = Presión inicial = 0.96 atm

P_2 = Presión final

V_1 = Volumen inicial = 95 mL

V_2 = Volumen final = 35 mL

En este problema usaremos la ley de Boyle.

\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=\dfrac{0.96\times 95}{35}\\\Rightarrow P_1=2.61\ \text{atm}

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4 0
3 years ago
Agent Bond is standing on a bridge, 17 m above the road below, and his pursuers are getting too close for comfort. He spots a fl
faust18 [17]

Answer:

2 poles

Explanation:

We are told Agent Bond is standing on a bridge, 17 m above the road below.

Now, the bed of the truck is 1.5 m above the road.

It means the distance hewill need to fall = 17 - 1.5 = 15.5 m

acceleration due to gravity = 9.8 m/s²

Initial velocity = 0 m/s

Thus, to find the time, we will use the equation;

s = ut + ½at²

Plugging in the relevant values gives;

15.5 = 0 + ½9.8t²

Multiply through by 2 to give;

15.5 × 2 = 9.8t²

31 = 9.8t²

t² = 31/9.8

t = √(31/9.8)

t = 1.78 sec

We are told that he spots a flatbed truck approaching at 28 m/s and that the telephone poles are 22m apart.

Thus; The truck will pass the poles at a rate of; Velocity/distance between poles = 28/22 = 1.273 poles per second

Since, we got the time to be 1.78 seconds, then we can find the number of poles by multiplying it with the rate of poles per seconds.

Thus;

Number of poles = 1.78 second × 1.273 poles/ seconds = 2.27 poles

This is approximately 2 poles

6 0
3 years ago
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