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kirill115 [55]
2 years ago
12

An object with density of 0.8g/ml will float in water

Physics
1 answer:
krok68 [10]2 years ago
6 0

Answer:

yes because density of object is less than water (i..e 1)

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What is the magnitude of the torque that the axle must apply to prevent the disk from rotating?
mihalych1998 [28]

The required torque at the axle, is given by the difference between the

moments of the applied forces.

The torque required is <u>19.62 N·m counterclockwise</u>

Reasons:

The given parameters are;

Mass of the disk, m = 5.0 kg

Location of the axle = Half the radius of the disk

Diameter of the disk, D = 40 cm = 0.4 m

Applied mass, 0.1 m from the axle = 15 kg

Applied mass, 0.3 m from the axle = 10 kg

Required:

Magnitude of torque at the axle that prevent the disk from rotating

Solution:

Torque needed = Clockwise moment - Counterclockwise moment

Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m

Counterclockwise moment = 15 kg × 0.1 m  × 9.81 m/s² = 14.715 N·m

τ + Counterclockwise moment = Clockwise moment

τ + 14.715 N·m = 34.335 N·m

Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m

Torque required, τ = <u>19.62 N·m counterclockwise</u>

Learn more here:

brainly.com/question/19044661

brainly.com/question/19247046

<em>The probable question drawing obtained from a similar question online is attached</em>

7 0
2 years ago
Emotions refer to the act or process of knowing. True or False​
vaieri [72.5K]

Answer:

True

Explanation:

Because they are central to the human experience and are related to everything we do .

4 0
3 years ago
Do atoms have full outer energy level combine with other atoms
Pavlova-9 [17]
All of the Noble Gases, which are on the right side of the periodic table, have a full outer energy level. The elements that are Noble Gases are the following: <span>Neon Argon Krypton Xenon Radon Ununoctium. 

Hope this helps.</span>
8 0
3 years ago
If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 1030 kg, what is the average distance between the planet a
Levart [38]

Answer:

9.36*10^11 m

Explanation

Orbital velocity  v=√{(G*M)/R},

G = gravitational constant =6.67*10^-11 m³ kg⁻¹ s⁻²,

M = mass of the star

R =distance from the planet to the star.

v=ωR, with ω as the angular velocity and R the radius

ωR=√{(G*M)/R},

ω=2π/T,

T = orbital period of the planet

To get R we write the formula by making R the subject of the equation

(2π/T)*R=√{(G*M)/R}

{(2π/T)*R}²=[√{(G*M)/R}]²,

(4π²/T²)*R²=(G*M)/R,

(4π²/T²)*R³=G*M,

R³=(G*M*T²)/4π²,

R=∛{(G*M*T²)/4π²},

Substitute values

R=9.36*10^11 m

5 0
2 years ago
Please help!!A camera lens 13.3 cm from a
kumpel [21]

Answer:

f=1.92 cm

If ans is correct reply for explanation.

7 0
3 years ago
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