Answer:
A
Explanation:
The ability to combine with oxygen is not a physical property it is a physical change i believe.
boiling point is a property as well as conducting electricity and hardness
Peptide bonds, hydrogen bonds, disulfide linkages, van der Waals, and electrostatic forces of attraction are the chemical bonds that stabilize the different structures in primary, secondary, tertiary, and quaternary structures.
The advanced structure of proteins gives rise to two kinds of major molecular shapes which are fibrous as well as globular structures. The main forces which are involved in stabilizing the secondary along with the tertiary structures of proteins include hydrogen bonds, disulfide type linkages, van der Waals attraction, and electrostatic forces of attraction.
The primary structure is generally determined by adjoining peptide bonds where the link is adjoining amino acids in sequential order. Tertiary structure is determined by the existence of disulfide bonds in between hydrophobic interactions as well as cysteine residues whereas the quaternary type structure is determined by multiple subunits of a protein that undergo various interactions.
Hydrogen bonds exist in a protein molecule as its large number can form between adjacent regions of the polypeptide chain in folded form and stabilize its three-dimensional kind of shape.
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Answer:
The rate of disappearance of 
is 0.0766 M/s.
Explanation:
Rate of the reaction = R
![R=-\frac{1}{1}\frac{d[C_2H_4]}{dt}=-\frac{1}{3}\frac{d[O_2]}{dt}](https://tex.z-dn.net/?f=R%3D-%5Cfrac%7B1%7D%7B1%7D%5Cfrac%7Bd%5BC_2H_4%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BO_2%5D%7D%7Bdt%7D)
[te]R=\frac{1}{2}\frac{d[CO_2]}{dt}=\frac{1}{2}\frac{d[H_2O]}{dt}[/tex]
Rate of disappearance of 
=0.23 M/s
Rate of disappearance of 
R =0.07666 M/s
Rate of disappearance of 
![\frac{d[C_2H_4]}{dt}=1\times 0.23 m/s=0.0766 M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BC_2H_4%5D%7D%7Bdt%7D%3D1%5Ctimes%200.23%20m%2Fs%3D0.0766%20M%2Fs)
The rate of disappearance of is 0.0766 M/s.
Answer:
The unknown element is Sb
Explanation:
The first thing we must note is that the unknown element must be a member of group 15 in the periodic table. This is clear from the fact that the two oxides formed are X2O3 and X2O5. This implies that the unknown element X must have a valency of 3 or 5. This corresponds to our knowledge that the outermost electron configuration of group 15 elements is ns2np3. Hence, group fifteen elements can have a valency of 3 or 5.
The electronic configuration of antimony is; [Kr]4d10 5s2 5p3. This implies that the atom is paramagnetic since there are three unpaired 5p electrons. The oxides of antimony are known to be amphoteric. An ampohoteric oxide reacts with both acid and base, hence the answer.
