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AleksandrR [38]

3 years ago

10

Two cubes, one silver and one iron, have the same mass and temperature. A quantity Q of heat is removed from each cube. Which on

e of the following properties causes the final temperatures of the cubes to be different?
A) density
B) latent heat of vaporization
C) specific heat capacity
D) coefficient of volume expansion
E) volume

1 answer:

scoundrel [369]3 years ago

8 0

Answer:

C) specific heat capacity

Explanation:

As we know that heat given to the system to change the temperature is given as

$Q = ms \Delta T$

here we know that

Q = thermal energy given to the system

s = specific heat capacity of the system

$\Delta T$ = change in temperature

so here we know that

$\Delta T = \frac{Q}{ms}$

here we know that heat given to the two cubes is of same amount as well as the mass is same but the final temperature is different because of the specific heat capacity (s)

So correct answer would be

C) specific heat capacity

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A student pulls horizontally on a block with a spring scale. The block reads 24.5 Newtons before the block starts to move. It re

Ahat [919]

Answer:

The coefficient of friction causes the force on the object to be less than its initial reading on the spring scale.

Explanation:

Since the block reads 24.5 N before the block starts to move, this is its weight. Now, when the block starts to move at a constant velocity, it experiences a frictional force which is equal to the force with which the student pulls.

Now, since the velocity is constant so, there is no acceleration and thus, the net force is zero.

Let F = force applied and f = frictional force = μN = μW where μ = coefficient of friction and N = normal force. The normal force also equals the weight of the object W.

Now, since F - f = ma and a = 0 where a = acceleration and m = mass of block,

F - f = m(0) = 0

F - f = 0

F = f

Since the force applied equals the frictional force, we have that

F = μW and F = 23.7 N and W = 24.5 N

So, 23.7 N = μ(24.5 N)

μ = 23.7 N/24.5 N

μ = 0.97

Since μ = 0.97 < 1, the coefficient of friction causes the force on the object to be less than its initial reading on the spring scale.

7 0

2 years ago

Which goes faster? *<br> light in space<br> sound in air<br> sound in space<br> light in water

andrezito [222]

Answer:

Hello! Your answer is, sound in the air is faster

Explanation:

The speed of sound through air is about 340 meters per second. It's faster through water and it's even faster through steel. Light will travel through a vacuum at 300 million meters per second. So they're totally different scales.

Hope I helped! Ask me anything if you have any questions! Brainiest plz. Hope you make an 100% and have a nice day! -Amelia♥

8 0

3 years ago

How many protons are in the radioactive isotope 40/19K?

trasher [3.6K]

First we have to establish that the number of protons is equivalent to the atomic number of element. Here I am assuming that you are referring to Potassium (K) - 40. Potassium, stable or unstable has 19 protons.

8 0

3 years ago

Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.383. At what minimum rate wo

djverab [1.8K]

Answer:

25.59 m/s²

Explanation:

Using the formula for the force of static friction:

$f_s = \mu_s N$ --- (1)

where;

$f_s =$ static friction force

$\mu_s =$ coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

$N = ma_{min}$

From equation (1)

$f_s = \mu_s ma_{min}$

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

$F = f_s$

$mg = \mu_s ma_{min}$

$a_{min} = \dfrac{mg }{ \mu_s m}$

$a_{min} = \dfrac{g }{ \mu_s }$

where;

$\mu_s = 0.383$ and g = 9.8 m/s²

$a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }$

$\mathbf{a_{min}= 25.59 \ m/s^2}$

3 0

2 years ago

An athlete kicks a soccer ball that starts at rest so that it leaves their foot with a speed of 10m/s from the top o f a rectang

kirza4 [7]

Answer:

$a=500m/s^2$

Explanation:

We need only to apply the definition of acceleration, which is:

$a=\frac{v_f-v_i}{t_f-t_i}$

In our case the final velocity is $v_f=10m/s$ , the initial velocity is $v_i=0m/s$ since it departs from rest, the final time is $t_f=0.02s$ and the initial time we are considering is $t_i=0s$

So for our values we have:

$a=\frac{10m/s-0m/s}{0.02s-0s}=500m/s^2$

3 0

3 years ago