What is the kinetic energy of a 620.0 kg roller coaster moving with a velocity of 9.00 m/s? Round to 3 significant figures.
2 answers:
You might be interested in
Answer:
0.181
Explanation:
We can convert the 0.5 rps into standard angular velocity unit rad/s knowing that each revolution is 2π:
ω = 0.5 rps = 0.5*2π = 3.14 rad/s
From here we can calculate the centripetal acceleration
Using Newton 2nd law we can calculate the centripetal force that pressing on the rider, as well as the reactive normal force:
Also the friction force and friction acceleration
For the rider to not slide down, friction acceleration must win over gravitational acceleration g = 9.81 m/s2:
Answer:
C. the product of the power rating of the light bulb and the time that it remains lit.
Explanation:
The power rating of the light is bulb is defined as the energy supplied to the light bulb divided by the time the bulb is lit up. Therefore,
where,
E = Energy Supplied to the bulb = Energy stored in capacitor = ?
P = Power rating of the bulb
t = time the bulb is lit up
Hence, the correct option is:
<u>C. the product of the power rating of the light bulb and the time that it remains lit.</u>