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iren2701 [21]
3 years ago
15

NEED HELP NOW I WILL BRAINLIEST

Physics
1 answer:
QveST [7]3 years ago
4 0

Answer:

C. 16 grams

Explanation:

0   0=2.7x0   256=256÷1

1    2.7=2.7x1   128=256÷2

2   5.4=2.7x2   64=128÷2

3   8.1=2.7x3   32=64÷2

4   10.8=2.7x4   ???=32÷2

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A volleyball player bumps a ball across a net with the velocity and angle shown below. What is the maximum height of the ball?
Marrrta [24]

Answer:

D. 12.4 m

Explanation:

Given that,

The initial velocity of the ball, u = 18 m/s

The angle at which the ball is projected, θ = 60°

The maximum height of the ball is given by the formula

                             h = u² sin²θ/2g  m

Where,

                           g - acceleration due to gravity. (9.8 m/s)

Substituting the values in the above equation

                            h = 18² · sin²60 / 2 x 9.8

                               = 18² x 0.75 / 2 x 9.8

                               = 12.4 m

Hence, the maximum height of the ball attained, h = 12.4 m

6 0
3 years ago
An object travels with a constant speed in a circular path. The net force on the object is
Pepsi [2]

Answer:

toward the center

Explanation:

Before answering, let's remind the first two Newton Laws:

1) An object at rest tends to stay at rest and an object moving at constant velocity tends to continue its motion at constant velocity, unless acted upon a net force

2) An object acted upon a net force F experiences an acceleration a according to the equation

F=ma

where m is the mass of the object.

In this problem, we have an object travelling at constant speed in a circular path. The fact that the trajectory of the object is circular means that the direction of motion of the object is constantly changing: this means that its velocity is changing, so it has an acceleration. And therefore, a net force is acting on it. The force that keeps the object travelling in the circular path is called centripetal force, and it is directed towards the center of the circle (because it prevents the object from continuing its motion straight away).

So, the correct answer is

toward the center

8 0
3 years ago
Two fixed charges, q1 = +1.07µC and q2 = -3.28µC, are 61.8cm apart. Where may a third charge be located so that no net force act
egoroff_w [7]

Answer:

12...lollll

Explanation:

.

3 0
3 years ago
Read 2 more answers
2. A woman prevents a 3kg brick from falling by pressing it against a vertical wall. The coefficient of friction
Anettt [7]
<h3>Answer:</h3>

49 N

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of the brick as 3 kg
  • The coefficient of friction as 0.6

We are required to determine the force that must be applied by the woman so the brick does not fall.

  • We need to importantly note that;
  • For the brick not to fall the, the force due to gravity is equal to the friction force acting on the brick.
  • That is; Friction force = Mg

But; Friction force = μ F

Therefore;

μ F = mg

0.6 F = 3 × 9.8

0.6 F = 29.4

      F = 49 N

Therefore, she must use a force of 49 N

6 0
3 years ago
At what stage of a reaction do atoms have the highest energy?
alekssr [168]
The correct answer for the question that is being presented above is this one: "c. transition state stage." During the transition state stage, the reaction of the atoms have the highest energy. It is also <span>during the formation of the activated complex in the middle of the experiment.</span>
3 0
3 years ago
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