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laiz [17]
3 years ago
10

Calculate the average distances the car and the washer traveled from the top of the track. Record the average in Table A of your

Student Guide. What is the average distance the car traveled from the top of the track? cm What is the average distance the washer traveled from the top of the track? cm
Physics
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0
The answer for both is 247 cm
KIM [24]3 years ago
7 0
Both is 247. hope it helps.
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Answer:

I think its C sorry if it's wrong

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A solution is a homogeneous mixture of one or more solutes dissolved in a solvent. A specific volume of solvent is only able to
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<h3><u>Answer;</u></h3>

C. Supersaturated

<h3><u>Explanation</u>;</h3>
  • Solutions are homogeneous mixtures that are created by mixing a solute and a solvent. Solute is the substance present in smaller amounts that dissolves in a solvent such as water which is the substance present in larger amount.
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You find it takes 200 N of horizontal force tomove an unloaded pickup truck along a level road at a speed of2.4 m/s. You then lo
IgorC [24]

ANSWER:

F(h)= 230 N is the horizontal force you will need to move the pickup along the same road at the same speed.

STEP-BY-STEP EXPLANATION:

F(h) is Horizontal Force = 200 N

V is Speed = 2.4 m/s

The total weight increase by 42%

coefficient of rolling friction decrease by 19%

Since the velocity is constant so acceleration is zero; a=0

Now the horizontal force required to move the pickup is equal to the frictional force.

F(h) = F(f)

F(h) = mg* u

m is mass

g is gravitational acceleration = 9.8 m/s^2

200 = mg*u

Since weight increases by 42% and friction coefficient decreases by 19%

New weight = 1+0.42 = 1.42 = (1.42*m*g)

New friction coefficient = μ = 1 - 0.19 = 0.81 = 0.81 u

F(h) = (0.81μ) (1.42 m g)

       = (0.81) (1.42) (μ m g)

       = (0.81) (1.42) (200)

       = 230 N

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3 years ago
Wyatt is moving a box with a mass of 37 kg a distance of 37 meters. Wyatt did 360 J of work in 2 minutes when moving the box. Wh
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His power output was 3 Watt (360 Joule/120 seconds). The power output can be calculated by dividing the quantity of work by the amount of second needed for the activity and also by multiplying the force amount with the velocity of the activity. The power output usually used for measuring the ability of machine for doing its job.
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Pls help me, tomorrow is the deadline of my assignment ​
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