The projectile has a height <em>h</em> at time <em>t</em> given by
<em>h</em> = (14.0 m/s) <em>t</em> - 1/2 <em>g t</em> ²
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve for <em>t</em> when <em>h</em> = 0 :
0 = (14.0 m/s) <em>t</em> - 1/2 <em>g t</em> ²
0 = 1/2 <em>t</em> (28.0 m/s - <em>g t</em> )
1/2 <em>t</em> = 0 <u>or</u> 28.0 m/s - <em>g</em> <em>t</em> = 0
The first equation says <em>t</em> = 0, which refers to the moment the gun is first fired, so we ignore that solution. We're left with
28.0 m/s - <em>g t</em> = 0
<em>t</em> = (28.0 m/s) / <em>g</em>
<em>t</em> = (28.0 m/s) / (9.80 m/s²)
<em>t</em> ≈ 2.86 s
The magnitude and direction of the force on the charge is -12 N opposite the electric field
To calculate the force on a charge in an electric field, we make use of the formula below.
<u>Formula</u>
F = E×Q .......................... Equation 1
Where:
- F = Force on the charge
- E = Electric Field
- Q = charge
From the question,
Given:
Substitute these values into equation 1
Note: The negative sign indicates that the force is in the direction negative of the electric field.
Hence, The magnitude and direction of the force on the charge is -12 N opposite the electric field
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During a blood transfusion, a client develops chills and a headache. . Stopping the transfusion at once is the priority nursing action.
Overview. Your blood is made up of liquids and solids. The liquid portion, called plasma, is made up of water, salts, and proteins. More than half of blood is plasma. The solid part of blood contains red blood cells, white blood cells, and platelets.
Blood is a special bodily fluid. It consists of four main components: plasma, red blood cells, white blood cells, and platelets. Blood has many functions, including Transporting oxygen and nutrients to the lungs and tissues. Formation of blood clots to prevent excessive blood loss. The main function of red blood cells is to carry oxygen from the lungs to the tissues of the body. It then transports carbon dioxide out of the tissues as a waste product and back to the lungs. Hemoglobin is an important protein in red blood cells that carries oxygen from the lungs to all parts of the body.
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A:a diver jumping Off a diving Board And falling to the swimming pool below
By calculation, the diameter of the wire is 2.8 * 10^-3 m.
<h3>How do we obtain the length?</h3>
The following data are given in the question;
Mass of the wire = 1.0 g or 1 * 10^-3 Kg
Resistance = 0.5 ohm
Resistivity of copper = 1.7 * 10^-8 ohm meter
Density of copper = 8.92 * 10^3 Kg/m^3
V = m/d
But v = Al
Al = m/d
A = m/ld
Resistance = ρl/A
= ρl/m/ld =
l^2 = Rm/ρd
l = √ Rm/ρd
l = √0.5 * 1 * 10^-3 / 1.7 * 10^-8 * 8.92 * 10^3
l = 1.82 m
A = πr^2
Also;
A = m/ld
A = 1 * 10^-3 Kg / 1.82 m * 8.92 * 10^3 Kg/m^3
Area of the wire = 6.2 * 10^-5 m^2
r^2 = A/ π
r = √A/ π
r = √6.2 * 10^-5 m^2/3.142
r = 1.4 * 10^-3 m
Diameter = 2r = 2( 1.4 * 10^-3 m) = 2.8 * 10^-3 m
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Missing parts;
Suppose you wish to fabricate a uniform wire from 1.00g of copper. If the wire is to have a resistance of R=0.500Ω and all the copper is to be used, what must be (a) the length and (b) the diameter of this wire?