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xxTIMURxx [149]
3 years ago
14

How many moles of Fe contains 3.41 x 1023 Fe atoms?

Chemistry
2 answers:
Liula [17]3 years ago
8 0

Answer:

Explanation:

28个

ValentinkaMS [17]3 years ago
5 0

Answer:

\boxed {\boxed {\sf  0.566 \ mol \ Fe}}

Explanation:

We are asked to convert a number of atoms to moles.  

We can convert atoms to moles using Avogadro's Number, which is 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this problem, the particles are atoms of iron (Fe). There are <u>6.022 ×10²³ atoms of iron in 1 mole of iron</u>.  

We use dimensional analysis to convert atoms to moles. This involves setting up ratios. Use Avogadro's Number and the underlined information to make a ratio.

\frac {6.022 \times 10^{23}\ atoms \ Fe}{1 \ mol \ Fe}

We are converting 3.41 × 10²³ atoms of iron to moles, so we multiply by this value.

3.41 \times 10^{23} \ atoms \ Fe *\frac {6.022 \times 10^{23}\ atoms \ Fe}{1 \ mol \ Fe}

Flip the ratio. It stays equivalent, but it allows the units of atoms of iron to cancel.

3.41 \times 10^{23} \ atoms \ Fe *\frac{1 \ mol \ Fe} {6.022 \times 10^{23}\ atoms \ Fe}

3.41 \times 10^{23}*\frac{1 \ mol \ Fe} {6.022 \times 10^{23}}

\frac{3.41 \times 10^{23}} {6.022 \times 10^{23}} \ mol \ Fe

0.5662570575\ mol \ Fe

The original measure ment of iron atoms ( 3.41 × 10²³ ) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandths place. The 2 in the ten-thousandths place ( 0.566<u>2</u>570575) tells us to leave the 6 in the thousandths place.

0.566 \ mol \ Fe

3.41 × 10²³ atoms of iron is equal to approximately <u>0.566 moles of iron.</u>

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Answer:

The answer to your question is d. 0.5 M

Explanation:

Data

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K = 0.5

Concentration of B and C at equilibrium = x

Concentration of A at equilibrium = 1 - x

Equation of equilibrium

                                       k = \frac{[B][C]}{A}

Substitution

                                       0.5 = \frac{[x][x]}{1 - x}

Simplification

                                       0.5 = \frac{x^{2}}{1 - x}

Solve for x

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                                      0.5 - 0.5x = x²

                                       x² + 0.5x - 0.5 = 0

Find the roots             x₁ = 0.5     x₂ = -1

There are no negative concentrations so the concentration of A at equilibrium is  

                       [A] = 1 - 0.5

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