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NISA [10]
2 years ago
5

For this discussion, respond to the following... An electron falls through a distance d in a uniform electric field of magnitude

E. Thereafter, the direction of the field is reversed (keeping its magnitude the same) and now a proton falls through the same distance. Compare, using quantitative reasoning, the time of fall in each case. Contrast this situation with that of objects falling freely under gravity. You will also need to post a response to at least two of your classmates' posts. Also, make sure that your response(s) are substantial and consist of at least 25 words.
Chemistry
1 answer:
mars1129 [50]2 years ago
4 0

The electron should experience a greater acceleration due to it's significantly smaller mass and should fall through distance "d" in a shorter amount of time.

<u>Explanation:</u>

The electron force can be expressed as F=qE. According to Newton's second law of motion force can be expressed as F=ma. This can be written as a=F/m. Substituting electric force expression for "F" in this equation, we get a=qE/m. This means acceleration is conversely proportional to mass and directly to electric field and charge. This means that proton having significantly larger mass than electron should experience smaller amount of acceleration and would take longer to fall at distance "d".

On the other hand, the electron would experience greater acceleration due to it's significantly smaller mass and would fall faster at distance "d", unlike the situation of proton.

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If a bullet travels at 407.0 m/s, what is its speed in miles per hour? Number click to edit mi/h For the same bullet travelling
kaheart [24]

Answer : The speed in miles per hour is 22 mile/hr.

The speed in yard per min is 26617.8 yard/min

Explanation :

The conversion used for meters to miles is:

1m=100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}

The conversion used for second to hour is:

1s=\frac{1}{60}min\times \frac{1hr}{60min}

The conversion used for meter per second to mile per hour is:

1\frac{m}{s}=\frac{100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}}{\frac{1}{60}min\times \frac{1hr}{60min}}

As we are given the speed of 407.0 meter per second. Now we have to determine the speed in miles per hour.

1m/s=2.2mile/hr

So, 407.0m/s=\frac{2.2mile/hr}{1m/s}\times 407.0m/s=895.4mile/hr

Therefore, the speed in miles per hour is 22 mile/hr.

The conversion used for meter to yard

1m = 1.09 yard

The conversion used for second to hour is:

1s=\frac{1}{60}min

The conversion used for meter per second to mile per hour is:

1m/s=\frac{1.09yard}{frac{1}{60min}}

1m/s=65.4yard/min

As we are given the speed of 407.0 meter per second. Now we have to determine the speed in yards per min

1m/s=65.4yard/min

So, 407.0m/s=\frac{65.4yard/min}{1m/s}\times 407.0m/s=26617.8yard/min

Therefore, the speed in yard per min is 26617.8 yard/min

7 0
2 years ago
A sodium atom can easily lose an electron. What happens to this electron?
meriva

Answer:

A.it is converted into thermal energy

4 0
2 years ago
If half of the moon is always illuminated why does its appearance from earth change?
irina [24]

Answer:

The different angles the moon has from sunlight to the earth

Explanation:

3 0
2 years ago
Read 2 more answers
The following five beakers, each containing a solution of sodium chloride (NaCl, also known as table salt), were found on a lab
mixas84 [53]

Answer:

See the answers below

Explanation:

1)  100. mL of solution containing 19.5 g of NaCl  (3.3M)

2)  100. mL of 3.00 M NaCl solution (3 M)

3) 150. mL of solution containing 19.5 g of NaCl  (2.2 M)

4)  Number 1 and 5 have the same concentration (1.5M)

MW of NaCl = 23 + 36 = 59 g

For number 3

          59 g ------------------- 1 mol

           19,5 g -----------------   x

  x = 19.5 x 1/59 = 0.33 mol

Molarity (M) = 0.33 mol/0.150 l = 2.2 M

For number 4,

Molarity (M) = 0.33mol/0.10 l = 3.3 M

For number 5

Molarity (M) = 0.450/0.3 = 1.5 M

4 0
3 years ago
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Which is stronger - the attractive forces between water molecules and chromium and chloride ions, or the combined ionic bond str
Tju [1.3M]

Answer is: the combined ionic bond strength of CrCl₂ and intermolecular forces between water molecules.

When chromium chloride (CrCl₂) is dissolved in water, the temperature of the water increases, heat of the solution is endothermic.

Dissociation of chromium chloride in water: CrCl₂(aq) → Cr²⁺(aq) + 2Cl⁻(aq).

Energy (the lattice energy) is required to pull apart the oppositely charged ions in chromium chloride.

The heat of hydration is liberated energy when the separated ions (in this example chromium cations and chlorine anions) attract polar water molecules.

Because the lattice energy is higher than the heat of the hydration (endothermic reaction), we can conclude that bonds between ions are strong (the electrostatic attraction between oppositely charged ions).

3 0
2 years ago
Read 2 more answers
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