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NISA [10]
3 years ago
5

For this discussion, respond to the following... An electron falls through a distance d in a uniform electric field of magnitude

E. Thereafter, the direction of the field is reversed (keeping its magnitude the same) and now a proton falls through the same distance. Compare, using quantitative reasoning, the time of fall in each case. Contrast this situation with that of objects falling freely under gravity. You will also need to post a response to at least two of your classmates' posts. Also, make sure that your response(s) are substantial and consist of at least 25 words.
Chemistry
1 answer:
mars1129 [50]3 years ago
4 0

The electron should experience a greater acceleration due to it's significantly smaller mass and should fall through distance "d" in a shorter amount of time.

<u>Explanation:</u>

The electron force can be expressed as F=qE. According to Newton's second law of motion force can be expressed as F=ma. This can be written as a=F/m. Substituting electric force expression for "F" in this equation, we get a=qE/m. This means acceleration is conversely proportional to mass and directly to electric field and charge. This means that proton having significantly larger mass than electron should experience smaller amount of acceleration and would take longer to fall at distance "d".

On the other hand, the electron would experience greater acceleration due to it's significantly smaller mass and would fall faster at distance "d", unlike the situation of proton.

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Answer and Explanation:

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The given value is:

The value of the mass of the water molecule is {eq}m_2=\rm 50\ grams {/eq}.

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Formula for Mass: Definition & Examples

from

Chapter 28 / Lesson 42

52K

What is mass? Learn the mass definition and how to find the mass of an object using the mass formula. See common mass characteristics and properties.

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Answer:

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Given parameters include:

Five μL of a 10-to-1 dilution of a sample; This implies the Volume of dilute sample is given as 5 μL

Dilution factor = 10-to-1

The absorbance at 595 nm was 0.78

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So, to determine the concentration of the diluted sample, we have:

concentration of diluted sample = \frac{mass}{volume}

= \frac{0.015 mg}{ 5 \alpha L}   (where ∝ was use in place of μ in the expressed fraction)

= 0.003 mg/μL

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protein concentration of the original solution = 10 × concentration of the diluted sample.

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