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NISA [10]
3 years ago
5

For this discussion, respond to the following... An electron falls through a distance d in a uniform electric field of magnitude

E. Thereafter, the direction of the field is reversed (keeping its magnitude the same) and now a proton falls through the same distance. Compare, using quantitative reasoning, the time of fall in each case. Contrast this situation with that of objects falling freely under gravity. You will also need to post a response to at least two of your classmates' posts. Also, make sure that your response(s) are substantial and consist of at least 25 words.
Chemistry
1 answer:
mars1129 [50]3 years ago
4 0

The electron should experience a greater acceleration due to it's significantly smaller mass and should fall through distance "d" in a shorter amount of time.

<u>Explanation:</u>

The electron force can be expressed as F=qE. According to Newton's second law of motion force can be expressed as F=ma. This can be written as a=F/m. Substituting electric force expression for "F" in this equation, we get a=qE/m. This means acceleration is conversely proportional to mass and directly to electric field and charge. This means that proton having significantly larger mass than electron should experience smaller amount of acceleration and would take longer to fall at distance "d".

On the other hand, the electron would experience greater acceleration due to it's significantly smaller mass and would fall faster at distance "d", unlike the situation of proton.

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What is the volume of 0.640 grams of Oz gas at Standard Temperature and Pressure (STP)?
Ilia_Sergeevich [38]

Answer: The volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

Explanation:

Given: Mass of O_{2} gas = 0.640 g

Pressure = 1.0 atm

Temperature = 273 K

As number of moles is the mass of substance divided by its molar mass.

So, moles of O_{2} (molar mass = 32.0 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.640 g}{32.0 g/mol}\\= 0.02 mol

Now, ideal gas equation is used to calculate the volume as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1.0 atm \times V = 0.02 mol \times 0.0821 L atm/mol K \times 273 K\\V = 0.449 L

Thus, we can conclude that the volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

6 0
3 years ago
In which reaction is there a transformation of mass into energy? For A P E X
Alik [6]
This is called
Nuclear fusion
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So the answer is A
5 0
3 years ago
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Hello! I just need a little bit of help. I'm supposed to design an experiment on how reaction rates are determined and affected
alexandr1967 [171]
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  2. Label the cups as ‘whole’, ‘pieces’, and ‘crushed’
  3. Next, get something to dissolve, in this case, polident. Take one of the polident tablets and break it into 4 pieces, and set it aside.
  4. Take another polident tablet and this time put it into a different cup, and crush it. Set it aside.
  5. Keep the last tablet whole.
  6. Set up your stopwatch and drop the polident tablet that is whole in the cup labeled ‘whole’, starting the stopwatch at the same time.
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Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day!

Stay Brainy!

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3 0
2 years ago
What is the number of moles in 500L of He gas at STP
kompoz [17]
Ah, this is actually a fairly simple chemistry question.

Recall that at STP, one mole is equivalent to 22.4 L. Knowing this, all you have to do is divide 500 L by 22.4 L to find the number of moles:

500/22.4 = 22.3 mol

-T.B.
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8_murik_8 [283]
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8 0
3 years ago
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