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Tom [10]
4 years ago
7

Which type of nuclear reaction involves combining light elements into a heavier element, with a resultant release of great amoun

ts of energy?
Question 14 options:

Combustion

Fusion

Fission

Radioactivity
Physics
2 answers:
torisob [31]4 years ago
8 0

Answer: Fusion

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

Nuclear fusion is a process which involves the conversion of two small nuclei to form a heavy nuclei along with release of energy.

_{94}^{239}\textrm{Pu}+_2^4\textrm{He}\rightarrow _{96}^{242}\textrm{Cm}+_0^\textrm{n}

Nuclear fission is a process which involves the conversion of a heavier nuclei into two or more small and stable nuclei along with the release of energy.

_{92}^{235}\textrm{U}+_0^1\textrm{n}\rightarrow _{36}^{91}\textrm{Kr}+_{56}^{142}\textrm{Ba}+_{0}^{1}\textrm{n}

natta225 [31]4 years ago
4 0

Answer: Fusion

Explanation: Fusion is a nuclear reaction in which light elements are combined into a heavier element, resulting in the release of great amounts of energy

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I’ve answered this problem before and there were 2 parts in this problem.

The solution would be like this for this specific problem:

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<span>0.002 * 3e8m/s = 0 + 2000m/s * ln(Mi / Mf) </span>
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<span>1.9e130 = Mi / Mf </span></span>

 

<span>B.    </span><span>4000m/s = 2000m/s * ln(Mi / Mf) </span><span>
<span>2 = ln(Mi / Mf) </span>
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3 0
3 years ago
A body moves due north with velocity 40 m/s. A force is applied
marshall27 [118]

Answer:

the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

Explanation:

The change in the momentum of a body, if the mass of the body is constant, is given by the following formula:

\Delta p=\Delta (mv)\\\\\Delta p=m\Delta v

p: momentum

m: mass

\Delta v:  change in the velocity

The sign of the change in the velocity determines the direction of rate of change. Then you have:

\Delta v=v_2-v_1

v2: final velocity = 35m/s

v1: initial velocity = 40m/s

\Delta v =35m/s-40m/s=-5m/s

Hence, the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

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3 years ago
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6 0
4 years ago
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If the oil thickness is 200 nm and the index is 1.5, what (vacuum) wavelength (in nm) does a diver see looking at the same posit
gavmur [86]

Answer: 133.33nm

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a = 200/ 1.5

a = 133.33nm

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