Answer:
Explanation:
To solve this problem we need to apply Kepler's third law.
Kepler's third law tells us that
Where
T= 320Days ( Period)
r = radius
G = Gravitational constant
M = Mass of the object, sun in this case
Then,
We need to re-arrange for R, so
Replacing
Therefore the radius of the star is
Explanation:
Given that,
Fundamental frequency of the string, f = 65.4 Hz
Length of the string, l = 0.6 m
Mass, m = 14.4 g = 0.0144 kg
(a) Let is the mass per unit length of the string. It can be calculated as :
(b) If f is the fundamental frequency of the string, the wavelength of the fundamental mode is given by :
n = 1
Hence, this is the required solution.
Electrical force between the two charges is (attractive)
Explanation:
The magnitude of the electrostatic force between two charged particles is given by Coulomb's law:
where:
is the Coulomb's constant
are the charges of the two particles
r is the separation between the two particles
In this problem, we have:
is the charge of the first particle
is the charge of the second particle
r = 3 m is the separation between them
Substituting into the formula, we find the force:
And the negative sign means the force is attractive (the electric force between two charges with opposite sign is attractive)
Learn more about electric force:
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Answer:
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