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ladessa [460]
3 years ago
14

on a standard position vs time graph, the distance between two points on the horizontal axis represents the time interval, and t

he distance between two points on the vertical axis is the displacement. the slope of the line represents the average velocity
Physics
1 answer:
Stels [109]3 years ago
3 0

Answer: true

Explanation: I got the question and guessed true and it was right

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An object of mass 700700 kg is released from rest 20002000 m above the ground and allowed to fall under the influence of gravity
qwelly [4]

Answer:

59.503987 seconds

Explanation:

b = Proportionality constant = 50 Ns/m

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of object = 700 kg

We have the equation of velocity

v(t)=\dfrac{mg}{b}+\left(V_0-\dfrac{mg}{b}\right)e^{\dfrac{bt}{m}}

The equation of motion

x(t)=\dfrac{mg}{b}+\dfrac{m}{b}\left(V_0-\dfrac{mg}{b}\right)(1-e^{\dfrac{bt}{m}})

x(t)=\dfrac{700\times 9.81}{50}+\dfrac{9.81}{50}\left(0-\dfrac{700\times 9.81}{50}\right)(1-e^{\dfrac{50t}{700}})

when x(t)=2000

2000=\dfrac{700\times 9.81}{50}+\dfrac{9.81}{50}\left(0-\dfrac{700\times 9.81}{50}\right)(1-e^{\dfrac{50t}{700}})\\\Rightarrow 2000\times \:50=\frac{700\times \:9.81}{50}\times \:50+\frac{9.81}{50}\left(0-\frac{700\times \:9.81}{50}\right)\left(1-e^{\frac{50t}{700}}\right)\times \:50\\\Rightarrow 6867-\frac{67365.27}{50}\left(1-e^{\frac{50t}{700}}\right)=100000\\\Rightarrow 50\left(-\frac{67365.27}{50}\left(1-e^{\frac{50t}{700}}\right)\right)=93133\times \:50\\\Rightarrow \frac{-67365.27\left(1-e^{\frac{50t}{700}}\right)}{-67365.27}=\frac{4656650}{-67365.27}\\\Rightarrow 1-e^{\frac{50t}{700}}=-69.12538\dots\\\Rightarrow -e^{\frac{50t}{700}}=-70.12538\dots\\\Rightarrow t=14\ln \left(70.12538\dots \right)\\\Rightarrow t=59.50398\ s

The time taken is 59.503987 seconds

8 0
3 years ago
Graphs are ____ of relationships.
sashaice [31]

Answer:

Diagrammatic representation

8 0
3 years ago
Which statement best describes the relationship between boron and silicon?
Lerok [7]
They have a diagonal relationship

8 0
3 years ago
Select all numbers that are correctly rounded
Andreas93 [3]
A and B i hope it helped 
7 0
2 years ago
A coiled telephone cord forms a spiral with 90.0 turns, a diameter of 1.30 cm, and an unstretched length of 57.0 cm. Determine t
Vinvika [58]

Answer:

2.36 μ H

Explanation:

Given,

Number of turns= 90

diameter = 1.3 cm = 0.013 m

unscratched length = 57 cm  = 0.57 m

Area, A = π r²

            = π x 0.0065² = 1.32 x 10⁻⁴ m²

 we know,

   L = \dfrac{\mu_0N^2A}{l}

   L = \dfrac{4\pi \times 10^{-7}\times 90^2\times 1.32\times 10^{-4}}{0.57}

    L = 2.36 μ H

Hence, the inductance of the unstretched cord is equal to 2.36 μ H

8 0
3 years ago
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