An object in a fluid experiences a buoyant force from the fluid. If the object is completely immersed, on which does the magnitu
1 answer:
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Answer : The velocity of an electron is,
Explanation :
According to de-Broglie, the expression for wavelength is,
and,
where,
p = momentum, m = mass, v = velocity
So, the formula will be:
.............(1)
where,
h = Planck's constant =
= wavelength =
m = mass of electron =
v = velocity of electron = ?
Now put all the given values in formula 1, we get:
Thus, the velocity of an electron is,
Answer:
(a) Magnitude: 14.4 N
(b) Away from the +6 µC charge
Explanation:
As the test charge has the same sign, the force that the other charges exert on it will be a repulsive force. The magnitude of each of the forces will be:
K is the Coulomb constant equal to 9*10^9 N*m^2/C^2, q and qtest is the charge of the particles, and r is the distance between the particles.
Let's say that a force that goes toward the +6 µC charge is positive, then:
The magnitude will be:
, away from the +6 µC charge
