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3 years ago

Help me please!!!!! I don’t get this!

Mathematics

2 answers:

Yakvenalex [24]3 years ago

8 0

The vertical axis is the same as the y axis and the horizontal axis is the same as the x axis. You're told that the y/vertical axis is inches and the x/horizontal axis is feet. Remember that there are 12 inches in a foot. That means y (number of inches) = 12x (12 times number of feet, x). So your equation is y = 12x.

You can plug some numbers into y = 12x, just to make sure this is the right equation. Let's try x = 1 foot. When x = 1, y = 12(1) = 12 inches. Yep! Let's try x = 2 feet. When x = 2, y = 12(2) = 24 inches. Yep!

That means y = 12x is the correct equation for your graph.

Remember that the general equation for slope-intercept form is y = mx + b. And m = the slope of the equation. (b = the y intercept, and x and y are your variables, aka the coordinate points on the graph, but that's not important in this question). You want the value of m, because that is the slope of the graph. Notice that m is multiplied by x. In our equation, y = 12x, 12 is being multiplied by x. That means 12 is m, our slope!

The slope of the graph is F) 12.

velikii [3]3 years ago

4 0

I think its 1/12 cause it is inches to feet.

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How do you find a missing side of a triangle using SOH CAH TOA

katrin2010 [14]

Answer:

See explanation and attachment

Step-by-step explanation:

SOH CAH TOA is a mnemonic.

SOH means $\sin \theta=\frac{Opposite}{Hypotenuse}$

CAH means $\cos \theta =\frac{Opposite}{Hypotenuse}$

TOA means $\tan \theta=\frac{Opposite}{Adjacent}$

Given an angle and a side of a right angle triangle, you can use the appropriate ratio to find the missing side.

For instance, find x in the diagram in the attachment.

In this case the best ratio to use is TOA.

$\tan 60\degree=\frac{\sqrt{3} }{x}$

$\implies x=\frac{\sqrt{3} }{\tan 60}$

$x=\frac{\sqrt{3} }{\sqrt{3} } =1$

All the other ratio also follow the same pattern

NB: Your calculator in degree should give $\tan 60\degree=\sqrt{3}$

3 0

2 years ago

Multiply or divide as indicated (3x)^12/(3x)^4

tresset_1 [31]

Answer:

Answer will be 6561 x ∧ 8

Step-by-step explanation:

Given that:

(3x) ∧ 12 / (3x) ∧ 4

3∧(12-4) * x ∧ (12-4)

3∧8 * x ∧ 8

6561 x∧8

5 0

3 years ago

Molly ordered 12 t-shirts for 14.00 and Teena ordered 23 t-shirts for 14.00 how much did they spend in all? Use the distributive

Cerrena [4.2K]

All together they spent 490

3 0

3 years ago

25+12 1/2 + 61/4+31/8+19/16+25/32=

Len [333]

Make them all have the same denominator
32

25+12 16/32+488/32+124/32+38/32+25/32

Add all of the numerators... to get 691/32+1184/32
1875/32
Simplify to get 58 19/32

4 0

3 years ago

There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the sampling distribution of the sampling proportions.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

2 years ago