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Xelga [282]
3 years ago
10

A rocket is moving through space on one thruster, if the mass of the astronaut is somehow doubled, but not the amount of time th

e rockets were fired, then the speed would be
Physics
2 answers:
lana [24]3 years ago
7 0
While the rockets are being fired the force is acting onto astronaut. According to a Newton's second law the formula is:
F = m * a

After the mass of the astronaut is doubled the force remains same. In order to get everything correct acceleration must be halved.
F = 2m * a/2

Smaller acceleration would result in smaller final speed. 
Korvikt [17]3 years ago
6 0

The speed would be reduced to half of the original speed.

Explanation

A rocket is propelled through space due to the forward momentum gained during thrusting for the amount of time the rockets were fired.

The amount of rocket firing time is proportional to the forward momentum obtained by the rocket to go through space.

If the mass of the astronaut is doubled but the amount of time the rockets were fired were kept same, this means that the momentum acquired by the rocket with doubled mass astronaut is tend to be same with the momentum acquired by the rocket without any change in the mass of astronaut.

It is known that momentum is directly proportional to mass and speed. So if the momentum tends to remain constant and the mass has to be doubled, then in order to propel with the same momentum, the speed should be reduced by half.

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0.0884 moles of a diatomic gas
Sloan [31]

Answer:

W = - 118.24 J (negative sign shows that work is done on piston)

Explanation:

First, we find the change in internal energy of the diatomic gas by using the following formula:

\Delta\ U = nC_{v}\Delta\ T

where,

ΔU = Change in internal energy of gas = ?

n = no. of moles of gas = 0.0884 mole

Cv = Molar Specific Heat at constant volume = 5R/2 (for diatomic gases)

Cv = 5(8.314 J/mol.K)/2 = 20.785 J/mol.K

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Therefore,

\Delta\ U = (0.0884\ moles)(20.785\ J/mol.K)(18.8\ K)\\\Delta\ U = 34.54\ J

Now, we can apply First Law of Thermodynamics as follows:

\Delta\ Q = \Delta\ U + W

where,

ΔQ = Heat flow = - 83.7 J (negative sign due to outflow)

W = Work done = ?

Therefore,

-83.7\ J = 34.54\ J + W\\W = -83.7\ J - 34.54\ J\\

<u>W = - 118.24 J (negative sign shows that work is done on piston)</u>

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Explain Energy Transformation using the image below and how the Law of Conservation of Energy is maintained.
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The chemical energy of petrol is converted to heat energy on combustion. The heat energy is converted to kinetic energy by the use of internal combustion engines in vehicles. The law of conservation of energy is maintained in each process.

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Given is a diagram of energy conversion due to combustion.

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In the given process, the mass decreases but energy remains the same in all forms of energy.

Hence, the law of conservation of energy is maintained in each process

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