Answer:
0.45 seconds
Explanation:
Letting the value of g = 10 m/s/s
final velocity (v) = 0 m/s (since the egg will come to rest at the maximum height)
initial velocity(u) = 4.5 m/s
acceleration = -10 m/s/s (since the gravity is acting against the egg)
time = t seconds
From the first equation of motion:
<em>v = u + at</em>
<em>0 = 4.5 + (-10)t</em>
<em>t = -4.5 / -10</em>
t = 0.45 seconds
Answer:
The observer sees the space-probe 9.055m long.
Explanation:
Let
be the length of the space-probe when measured at rest, and
be its length as observed by an observer moving at velocity
, then

Now, we know that
and
, and putting these into
we get:


Thus, an observer moving at 0.95c observes the space-probe to be 9.055m long.
The Correct Answer is <u>D.Infrared/</u> <em>INFARED has a lower frequency than visible light/</em>