Answer: The answer is B, The variable that should go on the x- axis is the temperature of water.
Explanation: In an experiment, we must have two variables; the independent variable and the dependent variable.
If the results of the experiment is reported in graphical format, the independent variable is plotted on the x axis while the dependent variable is plotted on the y axis.
In this case, the independent variable is the temperature of the water while the dependent variable is the mass of salt dissolved in 100 mL of water.
Therefore, the variable that should go on the x- axis is the temperature of water.
To solve this problem, we apply the concepts related to the sum of forces and balance in a diagram that will be attached, in order to identify the behavior, direction and sense of the forces. The objective is to find an expression that is in terms of the mass, the angle, the coefficient of friction and the length that allows us to identify when the ladder begins to slip. For equilibrium of the ladder we have,
![\sum F_x = 0](https://tex.z-dn.net/?f=%5Csum%20F_x%20%3D%200)
![\sum F_y = 0](https://tex.z-dn.net/?f=%5Csum%20F_y%20%3D%200)
![\sum M_o = 0](https://tex.z-dn.net/?f=%5Csum%20M_o%20%3D%200)
Now we have that
![f_1 = N_2](https://tex.z-dn.net/?f=f_1%20%3D%20N_2)
![N_1 = mg](https://tex.z-dn.net/?f=N_1%20%3D%20mg)
And for equilibrium of the two forces we have finally
![mgdcos\theta = N_2lsin\theta](https://tex.z-dn.net/?f=mgdcos%5Ctheta%20%3D%20N_2lsin%5Ctheta)
Rearranging to find the distance,
![d = \frac{N_2}{mg}ltan\theta](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7BN_2%7D%7Bmg%7Dltan%5Ctheta)
![d = \frac{f_1}{mg}ltan\theta](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7Bf_1%7D%7Bmg%7Dltan%5Ctheta)
So if we have that the frictional force is equivalent to
![f_1 = \mu N_1](https://tex.z-dn.net/?f=f_1%20%3D%20%5Cmu%20N_1)
![f_1 = \mu mg](https://tex.z-dn.net/?f=f_1%20%3D%20%5Cmu%20mg)
![f_1 = (0.4)(57*9.8)](https://tex.z-dn.net/?f=f_1%20%3D%20%280.4%29%2857%2A9.8%29)
![f_1 = 223.44N](https://tex.z-dn.net/?f=f_1%20%3D%20223.44N)
With this value we have that
![d = \frac{(0.4)(57)(9.8)}{57*9.8}(7.5) tan(60\°)](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B%280.4%29%2857%29%289.8%29%7D%7B57%2A9.8%7D%287.5%29%20tan%2860%5C%C2%B0%29)
![d = 5.19m](https://tex.z-dn.net/?f=d%20%3D%205.19m)
Therefore can go around to 5.19m before the ladder begins to slip.
Answer:
The planets and moons that orbit in the solar system.
Explanation:
For example the earth moves at 67,000 mph (107,000 km/h), and is constant from the gravitational pull of the sun. The moon orbits at about 2,288 mph (3,683 km/h). these are both traveling at different velocities but at a constant speed.
Answer:
option C
Explanation:
Given,
Refractive index of medium 1 = n₁
Refractive index of medium 2 = n₂
For total internal reflection to take place light should move from denser medium to the rarer medium.
Here Total internal reflection take place at the boundary of medium 1 and medium 2 so, the refractive index of medium 1 is more than medium 2
n₁ > n₂
The correct answer is option C
Incandescent lights get hot very quickly and therefore can easily burn u or catch fire