Answer:
In Newton's 1st Law, a stationary body or that moving with a uniform motion, will only change its state if acted upon by other external forces.This restance to change in position/motion is called inertia. In his second law, when a body is acted upon by a force, the force will be equal to the product of mass and acceleration of the body.i.e. Force= m.a. In the third law, it explains that a body will exert an equal and opposite force when intracting with another body.Here, every action force experiences an equal and opposite reaction force, where the momentum of the bodies will be conserved.
Answer:
Vrms = 291 m/s
Explanation:
The root mean square velocity or vrms is the square root of the average square velocity and is. vrms=√3RTM. Where M is equal to the molar mass of the molecule in kg/mol.
Temperature = 365 K
Root mean square velocity = ?
molar mass of oxygen = 16 g/mol.
But xygen gas (O2) is comprised of two oxygen atoms bonded together. Therefore:
molar mass of O2 = 2 x 16
molar mass of O2 = 32 g/mol
Convert this to kg/mol:
molar mass of O2 = 32 g/mol x 1 kg/1000 g
molar mass of O2 = 3.2 x 10-2 kg/mol
Molar mass of Oxygen = 3.2 x 10-2 kg/mol
Vrms = √[3(8.3145 (kg·m2/sec2)/K·mol)(365 K)/3.2 x 10-2 kg/mol]
Vrms = 291 m/s
Answer:
Explanation:
Time to cover first 100 km = 1 hour.
time remaining = 3.15 - 1 = 2.15 hour .
Time to cover next 42 km = 1 hour .
Time remaining = 2.15-1 = 1.15 hour.
Distance to be covered = 310 - 142
= 168 km
least speed needed = distance remaining / time remaining
= 168 / 1.15
= 146.08 km / h .
Answer:
1.635×10^-3m
Explanation:
Young modulus is the ratio of the tensile stress of a material to its tensile strain.
Young modulus = Tensile stress/tensile strain
Tensile stress = Force/Area
Given force = 130N
Area = Πr² = Π×(1.55×10^-3)²
Area = 4.87×10^-6m²
Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²
Tensile strain = extension/original length
Tensile strain = e/3.9
Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²
2×10¹¹N/m² = 8.39×10^7/{e/3.9)}
2×10¹¹ = (8.39×10^7×3.9)/e
2×10¹¹e = 3.27×10^8
e = 3.27×10^8/2×10¹¹
e = 1.635×10^-3m
The stretch of the steel wire will be
1.635×10^-3m
