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cupoosta [38]
3 years ago
7

a screwdriver with a 1-cm shaft and a 4-cm handle is used to tighten a screw. calculate the ideal mechanical advantage.

Physics
2 answers:
cricket20 [7]3 years ago
5 0
Ideal mechanical advantage = Effort distance/Resistance distance

In the current scenario,
Effort distance = 4 cm
Resistance distance = 1 cm

Therefore,
Ideal mechanical advantage = 4/1 = 4
vichka [17]3 years ago
5 0

Answer:

IMA = Distance of Effort/ Distance of resistance

Explanation:

M.A is the force amplification of a machine.

Ideally, a screw driver has varying diameters on two ends, the shaft and the handle, however, since the question does not provide those parameters, we will assume shaft and handle have the same diameter.

DE = 4

DR = 1

Therefore, IMA = \frac{4}{1} = 4

If diameter is given, IMA is calculated by

Area of Effort/ Area of resistance i.e. AE/AR

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3 years ago
An electron is initially moving at 1.4 x 107 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude 120 N
algol13

Answer:

K.E = 15.57 x 10⁻¹⁷ J

Explanation:

First, we find the acceleration of the electron by using the formula of electric field:

E = F/q

F = Eq

but, from Newton's 2nd Law:

F = ma

Comparing both equations, we get:

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q = charge of electron = 1.6 x 10⁻¹⁹ C

m = Mass of electron = 9.1 x 10⁻³¹ kg

Therefore,

a = (120 N/C)(1.6 x 10⁻¹⁹ C)/(9.1 x 10⁻³¹ kg)

a = 2.11 x 10¹³ m/s²

Now, we need to find the final velocity of the electron. Using 3rd equation of motion:

2as = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 1.4 x 10⁷ m/s

s = distance = 3.5 m

Therefore,

(2)(2.11 x 10¹³ m/s²)(3.5 m) = Vf² - (1.4 x 10⁷)²

Vf = √(1.477 x 10¹⁴ m²/s² + 1.96 x 10¹⁴ m²/s²)

Vf = 1.85 x 10⁷ m/s

Now, we find the kinetic energy of electron at the end of the motion:

K.E = (0.5)(m)(Vf)²

K.E = (0.5)(9.1 x 10⁻³¹ kg)(1.85 x 10⁷ m/s)²

<u>K.E = 15.57 x 10⁻¹⁷ J</u>

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The kinetic energy is given by:

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