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shepuryov [24]
3 years ago
9

Wind power holds great promise for the united states because of the _____________, and experts believe wind energy could meet as

much as 20 percent of the nation’s energy needs
Physics
1 answer:
SIZIF [17.4K]3 years ago
6 0
Wind<span> power holds great promise for the united states because of the great wind power (capacity), and experts believe wind energy could meet as much as 20 percent of the nation’s energy needs . Texas is the state with most wind capacity. On the second place is Iowa and oh the third place Oklahoma. The wind farms produce clean energy that does not harm the environment.</span>
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A double-slit diffraction pattern is formed on a distant screen. If the separation between the slits decreases, what happens to
STALIN [3.7K]

Answer:

The distance between interference fringes increases.

Explanation:

In a double-slit diffraction pattern, the distance of the n-order fringe from the centre of the pattern is

y=\frac{n \lambda D}{d}

where \lambda is the wavelength of the light, D the distance of the screen, and d the separation between the slits.

If we take two adjacent fringes, n and (n+1), their distance is

\Delta y = \frac{(n+1)\lambda D}{d}-\frac{n\lambda D}{d}=\frac{\lambda D}{d}

so, we see that it is inversely proportional to the slit separation, d.

Therefore, if the separation between the slits decreases, the distance between the interference fringes increases.

6 0
3 years ago
Determine the moment of inertia Ixx of the mallet about the x-axis. The density of the wooden handle is 860 kg/m3 and that of th
Yuki888 [10]

Complete Question

Diagram for this  shown on the first uploaded image

Answer:

The moment of inertia Ixx of the mallet about the x-axis is I{xx}= 0.119 kg \cdot m^2

Explanation:

From the question we are told that

        The density `of wooden handle is  \rho_w = 860 kg/m^3

        The density `of soft-metal head  is \rho_s =8000kg/m^3

Generally the mass of the wooden can be mathematically obtained with this formula

          m_w = \rho_w A_w l_w

Where A_w is mass of wooden handle which is  mathematically obtain with the formula

             A_w = \frac{\pi}{4} d^2_w

Where d_w is the diameter  of the wooden handle which from the diagram is

       27mm = \frac{27}{1000} = 0.027m

So  A_w = \frac{\pi}{4} * 0.027^2

      l_w is the length of the the wooden handle which is given in the diagram as   l_w = 315mm = \frac{315}{1000} = 0.315m

Substituting these value into the formula for mass

      m_w = 860 * (\frac{\pi}{4} * 0.027^2 ) *0.315

            = 0.155kg

Generally the mass of the soft-metal head can be mathematically obtained with this formula

           m_s = \rho_s A_s l_s

Where A_s is mass of soft-metal head which is  mathematically obtain with the formula

            A_s = \frac{\pi}{4} d^2_s

Where d_s is the diameter  of the soft-metal head which from the diagram is            

       36mm = \frac{36}{1000} = 0.036m

So  A_s = \frac{\pi}{4} * 0.036^2

 l_s is the length of the the soft-metal head which is given in the diagram

     as   l_s = 90mm = \frac{90}{1000} = 0.090m

Substituting these value into the formula for mass  

                  m_s = 8000 * (\frac{\pi}{4} * 0.036^2 ) *0.090

                       =0.733kg

Generally the mass moment of inertia about x-axis for the wooden handle is

                  (I_{xx})_w  =    [\frac{1}{3}m_w + l_w^2 ]  

Substituting values

                   (I_{xx})_w  =    [\frac{1}{3}*0.155 + 0.315^2 ]

                              =5.12*10^{-3}kg \cdot m^2  

Generally the mass moment of inertia about x-axis for the soft-metal head is

    (I_{xx})_s = [\frac{1}{12}m_s l_s ^2 + b^2]

Where b is the distance from the centroid to the axis of the head which is mathematically given as

                   b=l_w +\frac{d_s}{2}

Substituting values

                 b = 0.315 + \frac{0.036}{2}

                    = 0.336m

Now substituting values into the formula for mass moment of inertia about x-axis for soft-metal head

                            (I_{xx})_s = [\frac{1}{12} *0.733*  0.090^2 + 0.336^2]

                                      =0.113 kg \cdot m^2

Generally the mass moment of inertia about x-axis is mathematically represented as

         I_{xx} = (I_{xx})_w + (I_{xx})_s

                = [\frac{1}{3}m_w + l_w^2 ] + [\frac{1}{12}m_s l_s ^2 + b^2]

Substituting values

        I_{xx} = 5.12*10^{-3} +0.113

               I{xx}= 0.119 kg \cdot m^2

             

             

8 0
3 years ago
List the 4 things technology can be.
inessss [21]

Technology can be the four things listed below...

  • Phones
  • Computers
  • TVs
  • Playstation or Xbox
6 0
3 years ago
Read 2 more answers
10. The Force between two objects is 2 Newtons. One object has a mass of 6.2kg.
insens350 [35]

Answer:

m_2=9.79\times 10^{12}\ kg

Explanation:

Given that.

The force between two objects, F = 2 N

Mass of object 1, m₁ = 6.2 kg

Distance between the center of one object to the center of the other  object, r = 45 m

We need to find the mass of the second object. Using the formula of gravitational force as follows :

F=\dfrac{Gm_1m_2}{r^2}\\\\m_2=\dfrac{Fr^2}{Gm_1}\\\\m_2=\dfrac{2\times (45)^2}{6.67\times 10^{-11}\times 6.2}\\\\m_2=9.79\times 10^{12}\ kg

So, the mass of the second object is 9.79\times 10^{12}\ kg

6 0
3 years ago
Convert 8 light years to Astronomical Units
marusya05 [52]

Answer:

505929 AU

Explanation:

As you may know, one light-year is equivalent to approximately 63241.1 Astronomical Units. To get your answer, simply multiply 63241.1 * 8 to get ≈505929 AU

5 0
3 years ago
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