The correct answer is c) 28 m/s.
Let's find the step-by-step solution. The motion of the monkey is an uniformly accelerated motion, with acceleration equal to
. The initial velocity of the monkey is zero, while the distance covered is S=40 m. Therefore, we can use the following relationship to find vf, the final velocity of the monkey:
from which
Answer:
net power is + 2.25 D
Explanation:
Given data
distance vision = -0.25 D
near vision = + 2.50 D
to find out
net power
solution
we have given a person lens power for near is - 0.25 diopter and lens power for near power is +2.50 diopter so
net power is sum of both the power vision
so
net power = distance + near power
put both value we get net power
net power = ( -0.25 D) + ( + 2.50 D)
net power = + 2.25 D
so net power is + 2.25 D
It has to due with numbers so I would say the last one!
Answer:
3.06m/s² to the east
Explanation:
Given parameters:
Mass of car = 2.5 x 10³kg
Force acting on the car = 7.65 x 10³N
Unknown:
Acceleration of the car = ?
Solution:
From Newton's second law of motion:
Force = mass x acceleration
Acceleration = 
= 
= 3.06m/s² to the east
Answer:
D
Explanation:
Work is not a vector but it is a scalar
