Answer:
6.45 g of iodine, I₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Zn + I₂ —> ZnI₂
Next, we shall determine the mass of Zn and I₂ that reacted from the balanced equation. This can be obtained as follow:
Molar mass of Zn = 65 g/mol
Mass of Zn from the balanced equation = 1 × 65 = 65 g
Molar mass of I₂ = 127 × 2 = 254 g/mol
Mass of I₂ from the balanced equation = 1 × 254 = 254 g
SUMMARY:
From the balanced equation above,
65 g of Zn reacted with 254g of I₂.
Finally, we shall determine the mass of f I₂ needed to react with 1.65 g of Zn. This can be obtained as follow:
From the balanced equation above,
65 g of Zn reacted with 254g of I₂.
Therefore, 1.65 g of Zn will react with = (1.65 × 254)/65 = 6.45 g of I₂.
Thus, 6.45 g of iodine, I₂ is needed for the reaction.
