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EleoNora [17]
2 years ago
8

Suppose you have two chains available to suspend an object in the air. Let’s also say that you can arrange the suspension howeve

r you like. Which arrangement would cause the least amount of tension on the chain or chains?
A. Image 3

B. Image 4

C. Image 2

D. Image 1

Physics
2 answers:
Liono4ka [1.6K]2 years ago
5 0
<h2>your answer is going to be image 1 that one looks the most decent </h2>
slavikrds [6]2 years ago
3 0

Answer:

Image 3

Explanation:

Both chains hold 1/2 of the weight of the block. (its the most "decent" answer)

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A horizontal spring with spring constant 750 N/m is attached to a wall. An athlete presses against the free end of the spring, c
ANTONII [103]

Answer:

37.5 N Hard

Explanation:

Hook's law: The force applied to an elastic material is directly proportional to the extension provided the elastic limit of the material is not exceeded.

Using the expression for hook's law,

F = ke.............. Equation 1

F = Force of the athlete, k = force constant of the spring, e = extension/compression of the spring.

Given: k = 750 N/m, e = 5.0 cm = 0.05 m

Substitute into equation 1

F = 750(0.05)

F = 37.5 N

Hence the athlete is pushing 37.5 N hard

4 0
3 years ago
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A 400-n block is dragged along a horizontal surface by an applied force as shown. the coefficient of kinetic friction is uk = 0.
gulaghasi [49]
The block moves with constant velocity: for Newton's second law, this means that the resultant of the forces acting on the block is zero, because the acceleration is zero.

We are only concerned about the horizontal direction, and there are only two forces acting along this direction: the force F pushing the block and the frictional force F_f acting against the motion. Since their resultant must be zero, we have:
F-F_f = 0
The frictional force is
F_f = \mu mg
where
\mu=0.4 is the coefficient of kinetic friction
mg=400 N is the weight of the block. 

Substituting these values, we find the magnitude of the force F:
F=F_f = \mu mg=(0.4 )(400 N)=160 N
4 0
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A car driving at 20 m/s accelerates continuously 2m/s2​ ​ for 3 seconds. What is its final velocity
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Answer: V= u+ at

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V= 26m/s

Explanation:

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