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EleoNora [17]
3 years ago
8

Suppose you have two chains available to suspend an object in the air. Let’s also say that you can arrange the suspension howeve

r you like. Which arrangement would cause the least amount of tension on the chain or chains?
A. Image 3

B. Image 4

C. Image 2

D. Image 1

Physics
2 answers:
Liono4ka [1.6K]3 years ago
5 0
<h2>your answer is going to be image 1 that one looks the most decent </h2>
slavikrds [6]3 years ago
3 0

Answer:

Image 3

Explanation:

Both chains hold 1/2 of the weight of the block. (its the most "decent" answer)

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Fill in the blank question.
puteri [66]
Answer is on the image with the explanation. I hope that might help you with the answers

4 0
1 year ago
Why doesn't the skateboarder roll as high each time she goes up the ramp
Westkost [7]

Answer:

The skater has mechanical/gravitational potential energy at the two meter mark. The skater gets to two meters high on the other end of the ramp. In terms of the conservation of energy, the skater will never go higher than two meter on the other end of the the ramp because energy can be neither created nor destroyed.

Explanation:

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6 0
3 years ago
Read 2 more answers
A compact car has a maximum acceleration of 2.0 m/s2 when it carries only the driver and has a total mass of 1100 kg . you may w
nadya68 [22]

According to Newton`s  law. Force exerted by car,

F = m a = 1100 kg \times 2 m/s^2 = 2200 \ N

After adding an additional 400 kg of mass, the force will be same therefore the acceleration

F = 2200 \ N = (1100 \ kg + 400 \ kg)  a \\\\ a = \frac{2200 \ N}{1500 \ kg} = 1.47 \ m/s^2

Thus, the acceleration after adding the masses is 1.47 \ m/s^2.

4 0
3 years ago
When four people with a combined mass of 320 kg
ale4655 [162]
Each person is 80kg. 320/4
4 0
3 years ago
Two objects are dropped from different heights at the same instant. If the first object takes 10.7 seconds to hit the ground and
Lubov Fominskaja [6]

Answer:

The answer to your question is : 521.8 m

Explanation:

Data:

Different heights

Time first object (tfo) = 10.7 s

Time second object (tso)= 14.8 s

Initial speed of both objects(vo) = 0 m/s

a = 9.81 m/s²

Formula:

h = vot + 1/2 (a)(t)² but vo = 0    so, h = 1/2 (a)(t)²

Then, height fo      h = 1/2 (9.81)(10.7)² = 561.6 m

          height so     h = 1/2(9,81)(14.8)² = 1074.4 m

Difference in their heights =  1074.4 m - 561.6 m = 521.8 m

5 0
3 years ago
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