Suppose you have two chains available to suspend an object in the air. Let’s also say that you can arrange the suspension howeve
r you like. Which arrangement would cause the least amount of tension on the chain or chains?
A. Image 3
B. Image 4
C. Image 2
D. Image 1
A. Image 3
B. Image 4
C. Image 2
D. Image 1
2 answers:
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Answer:
lower
Explanation:
The lower the value of the coefficient of friction, the lower the resistance to sliding.
The coefficient of friction is the ratio of the frictional force and the normal force pressing two surfaces in contact together.
U =
U is the coefficient of friction
F is the frictional force
N is the normal force
We see that coefficient of friction is directly proportional to frictional force.
Answer:
Explanation:
In this question we have given
we have to find
We know that
optical path difference for bright fringe is given as
Here,
n is order of fringe
and optical path difference for dark fringe is given as
since the light with wavelength produces its third-order bright fringe at the same place where the light with wavelength
produces its fourth dark fringe
it means
optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe
Therefore,
...............(1)
Put value of in equation (1)