Suppose you have two chains available to suspend an object in the air. Let’s also say that you can arrange the suspension howeve
r you like. Which arrangement would cause the least amount of tension on the chain or chains?
A. Image 3
B. Image 4
C. Image 2
D. Image 1
A. Image 3
B. Image 4
C. Image 2
D. Image 1
2 answers:
You might be interested in
Answer:
impulse = 8820 kg· or 8820 N·s
Explanation:
Impulse J is equal to the average force multiplied by the elapsed time Δt or in equation form, J =
Δt
As long as your force of 450 N is constant then that value is your average force and your elapsed time is 19.4 seconds.
Multiply these values.
You will get an impulse of 8820 kg· or 8820 N·s.
This question can be solved using the concept of friction energy.
The thermal energy change is b "258.4 J".
The change in thermal energy will be equal to the friction energy produced during the motion of the box.
where,
μ = coefficient of kinetic friction = 0.4
f = force applied = 38 N
d = distance traveled by the box = 17 m
Therefore,
<u>E = 258.4 J</u>
Learn more about friction energy here:
Answer:
x_{cm} = 4.644 10⁶ m
Explanation:
The center of mass is given by the equation
= 1 /
∑
Where M_{total} is the total masses of the system, is the distance between the particles and
is the masses of each body
Let's apply this equation to our problem
M = Me + m
M = 5.98 10²⁴ + 7.36 10²²
M = 605.36 10²² kg
Let's locate a reference system located in the center of the Earth
Let's calculate
x_{cm} = 1 / 605.36 10²² [Me 0 + 7.36 10²² 3.82 10⁸]
x_{cm} = 4.644 10⁶ m