2 years ago

Evaluate 3 plus the square root of x + 19 minus the square root of 2 x when x equals 6

Mathematics

1 answer:

monitta2 years ago

5 0

=3+*sqr root*6 +19 - *sqr root* 12
=21 + *sqr root* 6 - *sqr root* 12
= 21+ *sqr root* 6 - 2 square roots of 6

You might be interested in

According a person will devote 33 years to sleeping and watching TV. The number of years sleeping wil exceed the number of years

GaryK [48]

Answer:

Do u have a picture? I want to help

Step-by-step explanation:

5 0

3 years ago

Please help I’ll mark you as brainliest if correct!

Annette [7]

Answer:

25% decrease

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

XYZ-QRS, and the scale factor from XYZ to QRS is 2/5. what is the length of side RS?

nirvana33 [79]

The side length of Rs is dependent on QRS

4 0

3 years ago

Pls send the answer

luda_lava [24]

Answer:

$a = \dfrac{46}{17}$

$b = 0$

Step-by-step explanation:

$\dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} - \sqrt{3}} + \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} + \sqrt{3}} =$

$= \dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} - \sqrt{3}} \times \dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} + \sqrt{3}} + \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} + \sqrt{3}} \times \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} - \sqrt{3}}$

$= \dfrac{23 + 4\sqrt{15}}{17} + \dfrac{23 - 4\sqrt{15}}{17}$

$= \dfrac{46}{17}$

$a = \dfrac{46}{17}$

$b = 0$

4 0

2 years ago

What is the scientific notation of 0.000487

Yuliya22 [10]

0.000487=4.87⋅10−4.............

6 0

3 years ago