Protons and neutrons are in the Nucleus of an atom; electrons surround the nucleus through valance shells
Answer:
Energy dissipated = 13.453 Joules
Explanation:
In order to solve this problem, we first compute the gravitational potential energy the child has, and then find the kinetic energy at the lowest position.
The gravitational potential energy (relative to lowest position) is found as follows:
G.P.E = mass * gravity * height
Where, Height = 2 - 2 * Cos(34°)
Height = 0.3193 meters
G.P.E = 30 * 9.8 * 0.3193
G.P.E = 93.874 J
Kinetic energy:
K.E = 0.5 * mass * velocity^2
K.E = 0.5 * 30 * 2.31547^2
K.E = 80.421 J
Energy dissipated = G.P.E - K.E
Energy dissipated = 93.874 - 80.421
<u>Energy dissipated = 13.453 J</u>
Answer:9A
Explanation:
let the last wire be wire C
According to Kirchhoff's rule
the sum of all currents entering a junction must be equal to the sum of all currents leaving a junction
Ic=Ia+Ib
Ic= 4+5
Ic=9A
Answer:
V = –0.89m/s
Explanation:
Please see attachments below.
Explanation:
u=40
v=?
h=?
v²-u²=2gs
0²-40²=2×10×s
160=20s
s=160/20
=80m/s
total distance= upward distance ×downward distance
=80+80
=160m
total displacement=0 because u and v is the same.