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EleoNora [17]
3 years ago
8

Is fire a form of plasma

Physics
1 answer:
Genrish500 [490]3 years ago
8 0
When fir e is hot enough to be seen it is often plasma
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chubhunter [2.5K]
If the question is in Mastering physics online, then the answer is not that hard. in fact, it's about the wording... 

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3 0
4 years ago
A box of bananas weighing 40.0 N rests on a horizontal surface. The coefficient of static friction between the box and the surfa
Burka [1]

Answer:

(a) = 0 N

(b) = 2.4 N

Explanation:

given

box of banana weight = 40.0 N

coefficient of static friction  μ = 0.40

coefficient of kinetic friction = 0.20

a).  when no horizontal force is applied .

according to Newton 's third law of motion If there is no force applied to the box,so the frictional  force exerted is 0 N

b) magnitude of friction force

box and the box is initially at rest

    friction force =.Static friction coefficient × weight of the box

      friction force = 0.40 × 6

       friction force =  2.4 N

8 0
3 years ago
Jasmine broke the antenna on her radio receiver. How will this most likely affect Jasmine’s radio?
Alexeev081 [22]

Jasmine will not be able to receive radio connection and when she decides to use her radio, there may be much static noises

she will still be able to use items such as Aux, CD, and tapes

4 0
3 years ago
A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. It starts from rest and is pulled up a mine s
Ierofanga [76]

Answer:

a). P=11.04kW

b). Pmax=11.38 kW

c). Wt=6423.166kJ

Explanation:

The power of the motor when the speed is constant is the work in a determinate time.

P=\frac{W}{t}

The work is the force the is applicated in a distance so

W=F*d

replacing:

P=F*\frac{d}{t} and \frac{d}{t} determinate distance in time is velocity so

a).

P=F*v

F=m*a\\F=m*g*sin(33.5)

P=950kg*9.8\frac{m}{s^{2}}*sin(33.5)*2.15\frac{m}{s}\\P=11047.846 W\\P=11.0478 kW

b).

The maximum power must the motor provide, is the maximum force with the maximum speed of the motor in this case

The first step is find the acceleration so

vi=0\frac{m}{s} \\vf=2.15 \frac{m}{s}\\vf=vi+a*t\\vf-vi=a*t\\ a=\frac{vf-vi}{t}= a=\frac{2.15\frac{m}{s}-0\frac{m}{s}}{13s}\\a=0.1653 \frac{m}{s^{2}}

The maximum force is when the car is accelerating so

Ft=Fa+Fg\\Ft=m*a+m*g*sin(33.5)\\Ft=950kg*0.1653\frac{m}{s^{2}}+950*9.8\frac{m}{s^{2}}*sin(33.5)\\Ft=5295.565 N

so the maximum force is the maximum force by the maximum speed

Pmax=Ft*v\\Pmax=5295.565N*2.15\frac{m}{s}\\Pmax=11385.46\\Pmax=11.3854kW

c).

The total energy transfer without any friction is the weight move in the high axis y in this case, so is easy to know that distance

W=m*g*h

h=Length*sin(33.5)

W=m*g*Length*sin(33.5)

W=950 kg*9.8* 1250m*sin(33.5)

W=6423166.667 kJ

W=6423.166 kJ

4 0
4 years ago
Hello jigxjufogonskdcxx ggnkctbntjc​
igor_vitrenko [27]

Answer:

svbsshsjjsjs Hello :)

7 0
4 years ago
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