<u>Final Velocity = 14m/s</u>
<u>Displacement = 56m</u>
Explanation:
U (initial velocity) = 2m/s
A (acceleration) = 3m/s^2
T (time) = 4s
v (final velocity) = ?
S (displacement) = ?
<u>FIRST FIND FINAL VELOCITY:</u>
(i) Multiply both sides by t:
(ii) Add u to both sides:
(iii) rearrange formula:
v = ( 3 × 4 ) + 2
v = 12 + 2
<u>v = 14m/s</u>
<u>SECOND FIND DISPLACEMENT:</u>
(i) Multiply both sides by t:
(ii) Rearrange formula:
s = 14 × 4
<u>s = 56m</u>
Not sure why it isn't one of the options but im pretty sure I did all the steps right...
It would mostly depend on its weight
The answer is south because the air friction is the opposite side of where the plane is going if that makes sense
Answer:
v=59[m/s]
Explanation:
To solve this problem we must use the principle of conservation of energy, which tells us that energy is transformed from Kinetic to potential or vice versa. At the moment when the car is at the top before falling down the cliff, we have the car moving at speed 50 [m/s] (kinetic energy) also it is 50 [m] above ground level (potential energy).
where:
Ek1 = kinetic energy before falling [J]
Ep1 = potential energy before falling [J]
Ek2 = kinetic energy in the ground [J]
The potential energy can be calculated by means of the following equation.
where:
m = mass = 500 [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 50 [m]
Whereas the kinetic energy can be calculated by means of the following equation.
where:
v = velocity = 50 [m/s]
Now replacing in the general equation: