Answer:
421.83 m.
Explanation:
The following data were obtained from the question:
Height (h) = 396.9 m
Initial velocity (u) = 46.87 m/s
Horizontal distance (s) =...?
First, we shall determine the time taken for the ball to get to the ground.
This can be calculated by doing the following:
t = √(2h/g)
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 396.9 m
Time (t) =.?
t = √(2h/g)
t = √(2 x 396.9 / 9.8)
t = √81
t = 9 secs.
Therefore, it took 9 secs fir the ball to get to the ground.
Finally, we shall determine the horizontal distance travelled by the ball as illustrated below:
Time (t) = 9 secs.
Initial velocity (u) = 46.87 m/s
Horizontal distance (s) =...?
s = ut
s = 46.87 x 9
s = 421.83 m
Therefore, the horizontal distance travelled by the ball is 421.83 m
Explanation:
Speed of Bob, v = 0.967 c
At the exact instant he passes Alice, she fires a very short laser pulse in the same direction Bob is moving.
(a) We need to find the distance measured by Alice between Bob and the laser pulse. It is given by :




(b) Distance measured by Bob between himself and the laser pulse is given by :



Hence, this is the required solution.
Answer:
P1 = 0 gage
P2 = 87.9 lb/ft³
Explanation:
Given data
Airplane flying = 200 mph = 293.33 ft/s
altitude height = 5000-ft
air velocity relative to the airplane = 273 mph = 400.4 ft/s
Solution
we know density at height 5000-ft is 2.04 ×
slug/ft³
so here P1 +
= P2 +
and here
P1 = 0 gage
because P1 = atmospheric pressure
and so here put here value and we get
P1 +
= P2 +
0 +
solve it we get
P2 = 87.9 lb/ft³
Injuries that are warm and not cold or hot.