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3 years ago

Numerical Problems:

Physics

1 answer:

dangina [55]3 years ago

6 0

Displacement=1200m
Time=4min=4(60)=240s

$\boxed{\sf Velocity=\dfrac{Displacement}{Time}}$

$\\ \sf\longmapsto Velocity=\dfrac{1200}{240}$

$\\ \sf\longmapsto Velocity=5m/s$

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What is the equation for finding the acceleration of an object moving in a straight line?

kiruha [24]

Acceleration can be found using one of the following suvat equations:

$v=u+at\\s=ut+\frac{1}{2}at^2\\s=vt-\frac{1}{2}at^2\\v^2-u^2=2as$

Explanation:

The acceleration of an object is defined as the rate of change of velocity of the object:

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time taken for the velocity to change from u to t

There are several equations used to find the acceleration of an object moving in a straight line (they are usually called suvat equation). Depending on which quantities are given in the problem, you can use one of the following equations:

$v=u+at\\s=ut+\frac{1}{2}at^2\\s=vt-\frac{1}{2}at^2\\v^2-u^2=2as$

where

$a$ is the acceleration

$s$ is the distance covered

$t$ is the time

$u$ is the initial velocity

$v$ is the final velocity

Learn more about acceleration and suvat equations:

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4 0

3 years ago

On a farm, you are pushing on a stubborn pig with a constant horizontal force with magnitude 30.0 n and direction 37.0° counterc

sashaice [31]

<span>Since the force is applied at an angle from the horizontal, we will use the horizontal component of this force in calculating for the displacements.
From derivation, the Fx is:</span>

Fx = F cos φ

Where:

Fx = is the horizontal component of the force

F = total force

φ = angle in radian = 37 * pi / 180 = 0.645 rad

Calculating: Fx = 30.0 N * cos(0.645)

Fx = 23.97 N = 24 N

Calculating for Work: W = Fx * d

A. W = 24 N * 15 m = 360 N

B. W = 24 N * 16 m = 384 N

C. W = 24 N * 12 m = 288 N

D. W = 24 N * 14 m = 336 N

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3 years ago

A car of mass 1600 kg traveling at 27.0 m/s is at the foot of a hill that rises vertically 135 m after travelling a distance of

Zarrin [17]

Answer:

Neglecting any frictional losses, the average power delivered by the car's engine is 10565 W

Explanation:

The energy conservation law indicates that the energy must be the same at the bottom of the hill and at the top of the hill.

The energy at the bottom is only the Kinect energy (K_1) of the car in motion, but in the top, the energy is the sum of its Kinect energy (K_2), potential energy (P) and the work (W) done by the engine.

$K_1 = K_2 + P + W$

then, the work done by the engine is:

$W = K_1 - K_2 - P$

The formulas for the Kinetic and potential energy are:

$K=\frac{1}{2}mV^2\\P=mgh$

where, m is the mass of the car, V the velocity, g the gravity and h is the elevation of the hill.

Using the formulas:

$W=\frac{1}{2}mV_1^2-\frac{1}{2}mV_2^2-mgh$

Replacing the values:

$W=\frac{1}{2}(1600Kg)(27m/s)^2-\frac{1}{2}(1600Kg)(14m/s)^2-(1600Kg)(9.8m/s^2)(135m)\\W=-1690400 J$

The negative of this value indicates the direction of the work done, but for the problem, you only care about the magnitude, so the power is W=1690400 J. Now, the power is equal to work/time so you need to find the time the car took to get to the top of the hill.

The average speed of the car is (27+14)/2=20m/s, and t=d/v so the time is:

$t=\frac{3200m}{20m/s}=160s$

the power delivered by the car's engine was:

$power=\frac{work}{time}=\frac{1690400J}{160s}=10565W$

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4 years ago

3. A car travelling at 20. m/s stops in a distance of 40. m. What is its

KIM [24]

Answer:

It was a joke i was getting the answer

Explanation:

Be percent karen

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NARA [144]

Answer:

Explanation:

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