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KATRIN_1 [288]
3 years ago
5

Numerical Problems:

Physics
1 answer:
dangina [55]3 years ago
6 0
  • Displacement=1200m
  • Time=4min=4(60)=240s

\boxed{\sf Velocity=\dfrac{Displacement}{Time}}

\\ \sf\longmapsto Velocity=\dfrac{1200}{240}

\\ \sf\longmapsto Velocity=5m/s

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One boat tows another boat by means of a tow line, which is under a constant tension of 465 N. The boats move at a constant spee
Ludmilka [50]

Answer:

Work done, W = 141174 Joules

Explanation:

It is given that,

Constant tension acting on the boat, T = F = 465 N

Speed of the boat, v = 4.6 m/s

Time, t = 1.1 min = 66 seconds

Let W is the work done by the tension. It is equal to the product of force and displacement. It is given by :

W=F\times d

Since, d=vt

W=F\times v\times t

W=465\ N\times 4.6\ m/s\times 66\ s

W = 141174 Joules

So, the work is done by the tension is 141174 Joules. Hence, this is the required solution.

6 0
3 years ago
how will you connect three resistors of 2 ohm centrioles and 5 ohms respectively so as obtain of the result and the resistance o
victus00 [196]

Two resistor of 2Ω in series parallel to resistor 5Ω in series to a 2Ω resistor. This configuration gives to us an equivalent resistor of 2.55Ω.

To solve this problem we have to use the rules of conection of resistor in series and parallel.

A resistor R1 in serie with other resistor R2 gives us an equivalent resistor Req= R1 + R2.

A resistor R1 in parallel with other resistor R2 gives us an equivalent resistor Req = R1.R2/R1+R2.

The circuit that show an arregement of resistor which we obtain a equivalent resistor of 2.5Ω from three resistor of 2Ω and 5Ω respectively is attached in the image:

3 0
4 years ago
Mutations are always harmful. <br> true or false
masha68 [24]

Answer:

false

Explanation:

some can be harmful but not all

5 0
3 years ago
Read 2 more answers
Please help me with my question
Rufina [12.5K]
Number 1!!!!!!!!!!!!!

6 0
3 years ago
What is the average flow rate in cm3/s of gasoline to the engine of a car traveling at 100 km/h if it averages 10. 0 km/l?
DiKsa [7]

The answer is 2.78 \mathrm{~cm}^{3} / \mathrm{s}

Q=\frac{1 \mathrm{~L}}{10.0 \mathrm{~km}} \times \frac{100 \mathrm{~km}}{\mathrm{~h}} \times \frac{1 \mathrm{~h}}{36005} \times \frac{1000 \mathrm{~cm}^{3}}{\mathrm{~L}}=2.78 \mathrm{~cm}^{3} / \mathrm{s}

Thus, the average flow rate is $2.78 \mathrm{~cm}^{3} / \mathrm{s}$.

What is average flow rate?

  • Average flow, which is often represented in cubic feet per second, refers to the stream's average discharge at a certain location.
  • The flowrate is the rate at which liquid travels through a pipe or into a wellbore from a reservoir.
  • The volume of fluid that moves across a specific cross-sectional area per unit of time is known as the flow rate.
  • It is essential to measure flow rates accurately using the right flowmeters to guarantee that fluid management procedures are efficient, safe, and cost-effective.

To learn more about Logistics visit: brainly.com/question/13385366

#SPJ4

4 0
2 years ago
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