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VARVARA [1.3K]
3 years ago
5

Write a short description/summary of your chosen galaxy, and pose two questions you have about the galaxy. Post both your summar

y and your questions on the discussion board. Be sure to respond to at least two questions that your classmates post.
Physics
1 answer:
mario62 [17]3 years ago
3 0

The milky way is the galaxy with the most known to human planets, it holds our sun, our moon, and many other moons, while only one other thing has been personally explored by us humans, there are facts we know of the planets in the galaxy

question: Why isn't pluto a planet anymore, and why cant we explore further into the galaxy.

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How does work affect energy between objects so it can cause a change in the form of energy? Work transfers energy. Work changes
IceJOKER [234]

'Doing work' is a way of transferring energy from one object to another, energy is transferred when a force moves through a distance.

If i explain with formula

Work done (J) = Energy transferred (J)

So more energy, more work done bc u transferred more energy to move the object and doing the work. and if you only use a little of energy, the work done also only a little.

4 0
3 years ago
1. What is the difference between a patent, latent, and plastic shoe<br> Impression?
Irina-Kira [14]

Answer:

Patent fingerprints can be made by blood, grease, ink, or dirt. This type of fingerprint is easily visible to the human eye. Plastic fingerprints are three-dimensional impressions and can be made by pressing your fingers in fresh paint, wax, soap, or tar.

I Hope this helps!

Sincerely; Victoria<3

Explanation:

4 0
3 years ago
Read 2 more answers
Heat is extracted from a certain quantity of steam at
vodomira [7]

Answer:v=2452.91 m/s

Explanation:

Given

initially steam is at 100^{\circ}C and converted to 0^{\circ} C ice

Let m be the mass of steam

latent heat of fusion and vaporization for water is

L_f=3.33\times 10^5 J/kg

L_v=2.26\times 10^6 J/kg

Heat required to convert steam in to water at 100^{\circ}C

Q_1=m\times L_v=m\cdot 2.26\times 10^6 J

Heat required to lower water temperature to 0^{\circ}C

Q_2=m\times c\times \Delta T

Q_2=m\times 4.184\times (100)

Q_2=4.184m\times 10^5 J

Heat required to convert 0^{\circ}C water to ice at 0^{\circ}C is

Q_3=m\times L_f

Q_3=m\times 3.33\times 10^5=3.33m\times 10^5 J

Q=Q_1+Q_2+Q_3

Q=(2.26+0.4184+0.33)m\times 10^6 J

Q=3.0084m\times 10^6 J

So this energy is equal to kinetic energy of  bullet of mass m moving with velocity v

Q=\frac{1}{2}mv^2

3.0084m\times 10^6=\frac{1}{2}mv^2

v^2=3.0084\times 2\times 10^6

v=2.452\times 10^3 m/s

v=2452.91 m/s  

5 0
4 years ago
As the wave interacts with a wall, which kind of wave interaction is shown?
kramer
Reflection-----------------------------
3 0
3 years ago
Read 2 more answers
How far must you be from a 110 W speaker to have an intensity of 0.0439 W/m^2? (Treat the speaker as a point source.)
Lina20 [59]

Answer:

d=14.12m

Explanation:

Assume a point sound source that emits a sound power<em> P </em>(in W) evenly in all directions of space. Let us also assume that the medium does not absorb this sound power when it passes through it. At a distance<em> d </em>from the source this power will have been evenly distributed over the surface of a sphere of radius <em>d</em>. Therefore, the acoustic intensity I at distance d will be worth:

I=\frac{P}{4\pi d^{2}}

This is the expression of the so-called<em> law of the square of distance: "the intensity is inversely proportional to the square of the distance to the source (considered punctual)".</em>

So

I=0.0439 \frac{W}{ m^{2}}

P=110W

d=\sqrt { \frac{P}{4 \pi\\I}

d=\sqrt{ \frac{110}{ 4\pi (0,0439)} }

d=\sqrt{{199.39}

d=14.12m

3 0
3 years ago
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