Answer:
Net charge contained in the cubeq= 3.536×10^-6C
Explanation:
Formular for total flux in a cube is given as:
Total flux= E300Acos(180) + E200Acos(0)
Where A is crossectional area
Total flux= A(E200-E300)
Total flux= q/Eo
q= Eo×total flux
q=(8.84×10^-12)×(100)^2×(100-60)
q= 3.536×10^-6C
Answer:
Rubber or plastic covers are bad conductors of electricity. So they do not allow the electric current to pass through it.
Explanation:
Rubber and plastic are bad conductors of electricity, therefore when handling a tool with a rubber handle, the electricity will not pass through it.
<span>net work = change in kinetic energy
for Block B, we just have the force from block A acting on it
F(ab)d= .5(1)vf² - .5(1)(2²)
F(ab)d= .5vf² - 2
Block A, we have the force from the hand going in one direction and the force of block B on A going the opposite direction
10-F(ba)d = .5(4)vf² - .5(4)(2²)
10-F(ba)d = 2vf² - 8
F(ba)d = 18 - 2vf²
now we have two equations:
F(ba)d = 18 - 2vf²
F(ab)d= .5vf² - 2
since the magnitude of F(ba) and F(ab) is the same, substitute and find vf (I already took into account the direction when solving for F(ab)
10-.5vf² + 2 = 2vf² - 8
12 - .5vf² = 2vf² - 8
20 = 2.5vf²
vf² = 8
they both will have the same velocity
KE of block A= .5(4)(2.828²) = 16 J
KE of block B=.5(1)(2.828²) = 4 J</span>
Answer:
3 mA.
Explanation:
The following data were obtained from the question:
Resistor (R) = 500 Ω
Potential difference (V) = 1.5 V
Current (I) =.?
Using the ohm's law equation, we can obtain the current as follow:
V = IR
1.5 = I x 500
Divide both side by 500
I = 1.5 / 500
I = 3×10¯³ A.
Therefore, the current in the circuit is 3×10¯³ A.
Finally, we shall convert 3×10¯³ A to milliampere (mA).
This can be obtained as follow:
Recall:
1 A = 1000 mA
Therefore,
3×10¯³ A = 3×10¯³ × 1000 = 3 mA
Therefore, 3×10¯³ A is equivalent to 3 mA.
Thus, the current in mA flowing through the circuit is 3 mA.
The total gauge pressure at the bottom of the cylinder would
simply be the sum of the pressure exerted by water and pressure exerted by the
oil.
The formula for calculating pressure in a column is:
P = ρ g h
Where,
P = gauge pressure
ρ = density of the liquid
g = gravitational acceleration
h = height of liquid
Adding the two pressures will give the total:
P total = (ρ g h)_water + (ρ g h)_oil
P total = (1000 kg / m^3) (9.8 m / s^2) (0.30 m) + (900 kg /
m^3) (9.8 m / s^2) (0.4 - 0.30 m)
P total = 2940 Pa + 882 Pa
P total = 3,822 Pa
Answer:
The total gauge
pressure at the bottom is 3,822 Pa.
