Please help with last equation i don't understand at all!!!

Need Help ASAP!!<br> (Picture)

olchik [2.2K]

Answer:225000000000

Explanation:

5 0

4 years ago

Which of the following diagrams accurately applies the Law of

nekit [7.7K]

The answer choices don’t make sense

8 0

3 years ago

Two long, parallel wires are separated by a distance of 3.80 cm . The force per unit length that each wire exerts on the other i

IgorLugansk [536]

Answer:

(a). I' = 17.24 A

(b).The current in second wire is in opposite direction compare to first wire.

Explanation:

Given data

r = 0.038 m

$\frac{F}{L} =$ 4.9 × $10^{-5}$ $\frac{N}{m}$

I = 0.54 A

(a). The current in the second wire is calculated as

$I'=\frac{F}{L} \frac{2 \pi r}{\mu I}$

Put all the values in above formula we get

$I' =$ $\frac{ (2) (3.14) (0.038)}{4 \pi (0.54)} 490$

I' = 17.24 A

(b). The current in the two wires is in opposite directions because the wires repeal each other. therefore the current in second wire is in opposite direction compare to first wire.

7 0

4 years ago

HURRY!!!!!!!!!!!!

Charra [1.4K]

Absolute dating and relative dating are both used commonly to determine the age of fossils. Absolute dating gives the exact date and chronological order to which the fossil lived. They do this by looking at the surrounding ground and using the carbon to find out how old it is. Relative dating is pretty similar to this except it uses carbon dating which is a way of finding the approximate age of the fossil. They do this by looking at the layers of the earth and making an assumption as to how old it is.

6 0

3 years ago

Read 2 more answers

A 10 kg frictionless cart is pushed at a constant force of 5.0 N for a distance of 10 m. The work done on the cart is 50J.

kykrilka [37]

1) Final kinetic energy of the cart: B) 50 J

2) Final speed of the cart: C) 3.2 m/s

3) Height reached along the ramp: A) 0.5 m

Explanation:

1)

We can solve this part of the problem by using the work-energy theorem, which states that the work done on an object is equal to the kinetic energy gained by the object itself. Mathematically:

$W=K_f - K_i$

where

W is the work done

$K_f$ is the final kinetic energy

$K_i$ is the initial kinetic energy

In this problem, the work done on the cart is

W = 50 J

And assuming it starts from rest, its initial kinetic energy is zero:

$K_i = 0$

Therefore, the final kinetic energy is:

$K_f = K_i + W=0+50=50 J$

2)

The kinetic energy of an object is the energy possessed by an object due to its motion; it is calculated as

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

For the cart in this problem, we have:

K = 50 J is its final kinetic energy

m = 10 kg is the cart

Therefore, solving the formula for v, we find its speed:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(50)}{10}}=3.2 m/s$

3)

We can think this problem in terms of conservation of energy. In fact, as the cart rolls up the ramp, its kinetic energy is converted into gravitational potential energy, which is given by

$PE=mgh$