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3 years ago

11

Which material are you most likely to find in the C horizon?

2 answers:

LekaFEV [45]3 years ago

8 0

the answer is parent material

monitta3 years ago

4 0

The answer is "B. Parent material".

A C horizon comprises of parent material, for example, frosty till or lake residue that have almost no change because of the dirt shaping procedures. Low force forms, for example, development of soluble salts or oxidation and decrease of iron may happen. There are no prevailing procedures in the C skyline; negligible increments and misfortunes of profoundly soluble material (e.g., salts) may happen.

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Korolek [52]

Answer:

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Explanation:

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3 years ago

Calculate the magnitude of the electric field at one corner of a square 2.42 m on a side if the other three corners are occupied

Karolina [17]

Ans:

12500 N/C

Explanation:

Side of square, a = 2.42 m

q = 4.25 x 10^-6 C

The formula for the electric field is given by

$E = \frac{Kq}{r^2}$

where, K be the constant = 9 x 10^9 Nm^2/c^2 and r be the distance between the two charges

According to the diagram

BD = $\sqrt{2}\times a$

where, a be the side of the square

So, Electric field at B due to charge at A

$E_{A}=\frac{Kq}{a^2}$

$E_{A}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}$

EA = 6531.32 N/C

Electric field at B due to charge at C

$E_{C}=\frac{Kq}{a^2}$

$E_{C}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}$

Ec = 6531.32 N/C

Electric field at B due to charge at D

$E_{D}=\frac{Kq}{2a^2}$

$E_{D}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2\times 2.42^2}$

ED = 3265.66 N/C

Now resolve the components along X axis and Y axis

Ex = EA + ED Cos 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

Ey = Ec + ED Sin 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

The resultant electric field at B is given by

$E=\sqrt{E_{x}^{2}+E_{y}^{2}}$

$E=\sqrt{8840.5^{2}+8840.5^{2}}$

E = 12500 N/C

Explanation:

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Read 2 more answers

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