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Masja [62]
3 years ago
11

What would be the new volume if the pressure of 600mL is increased from 100kPa to 150.56 kPa

Physics
1 answer:
Gelneren [198K]3 years ago
4 0

ASSUMING that the substance is a gas . . .

It all depends on HOW the pressure was increased.

-- IF the gas was left in the same container, and the pressure was increased by heating the container, then the volume hasn't changed. It's still the inside volume of the container.

-- IF the pressure was increased by stuffing all of the gas into a smaller container, then the new volume is the volume of the smaller container.

No matter what the mass or temperature of the gas is, it always expands to fill whatever container you're keeping it in.  

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8 0
3 years ago
As the temperature of an object increases, the wavelength of the brightest light emitted _______
alexira [117]

Answer:

option (B) decreases

Explanation:

According to the Wein's displacement law, the minimum wavelength of the radiated emission is inversely proportional to the absolute temperature of the body which emits radiation.

\lambda_{m}\alpha \frac{1}{T}

Where, T is the absolute temperature of the body and λm is the minimum wavelength of heat radiated.

Here, as the temperature increases, the wavelength decreases.

4 0
3 years ago
A 286-kg motorcycle is accelerating up along a ramp that is inclined 31.6° above the horizontal. The propulsion force pushing th
kkurt [141]

Answer:

The acceleration motorcycle

a = 5.13 m / s²

Explanation:

Now to determine the acceleration of the motorcycle

Use the force to analysis motion

∑ F = m * a

∑ F = E - D - m*g * sin ( β ) = m * a

E = 3168 N

D = 230 N

β = 31.6 °

3168 N - 230 N - 286 kg * 9.8 m / s² * sin ( 31.6° ) = 286 kg * a

Now solve to a'

a = [ 3168 N - 230 N - 286 kg * 9.8  m / s² * sin ( 31.6° ) ] / (286 kg)

a = 5.13 m / s²

7 0
3 years ago
What is the ratio of the intensities of an earthquake P wave passing through the Earth and detected at two points 14 km and 49 k
Molodets [167]

Answer:

\dfrac{I_1}{I_2}=12.25

Explanation:

r_1 = 14 km

r_2 = 49 km

Intensity of a wave is inversely proportional to distance

I\propto \dfrac{1}{r^2}

So,

\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{49^2}{14^2}\\\Rightarrow \dfrac{I_1}{I_2}=12.25

The ratio of the intensities is \dfrac{I_1}{I_2}=12.25

6 0
3 years ago
Two balls have their centers 2.0 m apart. One ball has a mass of m1 = 7.9 kg. The other has a mass of m2 = 6.1 kg. What is the g
maks197457 [2]

Answer:

3.036×10⁻¹⁰ N

Explanation:

From newton's law of universal gravitation,

F = Gm1m2/r² .............................. Equation 1

Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.

G = gravitational constant

Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²

Substituting into equation 1

F = 6.67×10⁻¹¹×7.9×6.1/2²

F = 321.427×10⁻¹¹/4

F = 30.36×10⁻¹¹

F = 3.036×10⁻¹⁰ N

Hence the force between the balls = 3.036×10⁻¹⁰ N

8 0
3 years ago
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