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Masja [62]
2 years ago
11

What would be the new volume if the pressure of 600mL is increased from 100kPa to 150.56 kPa

Physics
1 answer:
Gelneren [198K]2 years ago
4 0

ASSUMING that the substance is a gas . . .

It all depends on HOW the pressure was increased.

-- IF the gas was left in the same container, and the pressure was increased by heating the container, then the volume hasn't changed. It's still the inside volume of the container.

-- IF the pressure was increased by stuffing all of the gas into a smaller container, then the new volume is the volume of the smaller container.

No matter what the mass or temperature of the gas is, it always expands to fill whatever container you're keeping it in.  

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Answer:

The x-component of F_{3} is 56.148 newtons.

Explanation:

From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:

\vec F_{1} + \vec F_{2} + \vec F_{3} = \vec O (1)

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\vec F_{1}, \vec F_{2}, \vec F_{3} - External forces exerted on the ring, measured in newtons.

\vec O - Vector zero, measured in newtons.

If we know that \vec F_{1} = (70.711,70.711)\,[N], \vec F_{2} = (-126.859, 46.173)\,[N], F_{3} = (F_{3,x},F_{3,y}) and \vec O = (0,0)\,[N], then we construct the following system of linear equations:

\Sigma F_{x} = 70.711\,N - 126.859\,N +F_{3,x} = 0\,N (2)

\Sigma F_{y} = 70.711\,N + 46.173\,N+F_{3,y} = 0\,N (3)

The solution of this system is:

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The x-component of F_{3} is 56.148 newtons.

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