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maria [59]
2 years ago
6

A dart is thrown from 1.50 m high at 10.0 m/s toward a target 1.73 m from the ground. At what angle was the dart thrown?

Physics
1 answer:
Triss [41]2 years ago
6 0

Answer:

The angle of projection is 12.26⁰.

Explanation:

Given;

initial position of the dart, h₀ = 1.50 m

height above the ground reached by the dart, h₁ = 1.73 m

maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m

velocity of the dart, u = 10 m/s

The maximum height reached by the projectile is calculated as;

H_m = \frac{u^2sin^2 \theta}{2g}

where;

θ is angle of projection

g is acceleration due to gravity = 9.8 m/s²

H_m = \frac{u^2sin^2 \theta}{2g}\\\\sin^2 \theta = \frac{H_m \ \times \ 2g}{u^2} \\\\sin^2 \theta = \frac{0.23 \ \times \ 2(9.8)}{10^2} \\\\sin ^2\theta =0.04508\\\\sin \theta = \sqrt{0.04508} \\\\sin \theta = 0.2123\\\\\theta  = sin^{-1}(0.2123)\\\\\theta  = 12.26^0

Therefore, the angle of projection is 12.26⁰.

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Answer:

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1m_{u}=1.66054x10^{-27}kg

m_{u} is atomic mass unit.

This is why the benefits of the atomic mass unit is that it makes the representation of atomic masses easier in terms of the simplicity of the numbers that are used to represent the masses. Also using the atomic mass unit it is easier to compare the masses of different atoms, These numbers would be very small and would require negative powers of 10 to represent them, so it is more convenient to use the atomic mass unit.

3 0
3 years ago
A solid uniform disk of diameter 3.20 m and mass 42 kg rolls without slipping to the bottom of a hill, starting from rest. If th
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Answer:

A(3.56m)

Explanation:

We have a conservation of energy problem here as well. Potential energy is being converted into linear kinetic energy and rotational kinetic energy.

We are given ω= 4.27rad/s, so v = ωr, which is 6.832 m/s. Place your coordinate system at top of the hill so E initial is 0.

Ef= Ug+Klin+Krot= -mgh+1/2mv^2+1/2Iω^2

Since it is a solid uniform disk I= 1/2MR^2, so Krot will be 1/4Mv^2(r^2ω^2=  v^2).

Ef= -mgh+3/4mv^2

Since Ef=Ei=0

Mgh=3/4mv^2

gh=3/4v^2

h=0.75v^2/g

plug in givens to get h= 3.57m

5 0
3 years ago
A 7.00 g bullet, when fired from a gun into a 1.00 kg block of wood held in a vise, penetrates the block to a depth of 8.00 cm b
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Answer:

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3 years ago
A negative point charge q1 = 25 nC is located on the y axis at y = 0 and a positive point charge q2 = 10 nC is located at y =14
sergey [27]

Answer:

 y = 0.1 m

Explanation:

The electrical power for point loads is

         V = k \sum \frac{q_i}{r_i}k Sum qi / ri

in this case

         V = k (- \frac{q_1}{r_1 } + \frac{q_2}{r_2})

indicate that V = 0

        \frac{q_1}{r_1} = \frac{q_2}{r_2}

        r₂ = \frac{q_2}{q_1} r_1

the distance r1 is

         r₁ = y -0

the distance r2

         r₂ = 0.14 -y

we substitute

       

        0.14 - y = \frac{10}{25}  y

          y ( \frac{10}{25} + 1) = 0.14

          y 1.4 = 0.14

          y = 0.14 / 1.4

          y = 0.1 m

7 0
3 years ago
an object starts from rest with a constant acceleration of 8.0m/s^2 along a straight line.find the average speed for 5 second in
frozen [14]

Answer:

40 m/s

Explanation:

If you multiply the acceleration with time you get the average speed.

6 0
2 years ago
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