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Degger [83]
2 years ago
14

nolan ryan has the record for having the speediest fastball in baseball. he could pitch one at 148 i/sec. what is that speed in

mi/hr?
Physics
1 answer:
Klio2033 [76]2 years ago
5 0

The speed of the ball is 101miles/hr.

A mile is a unit of length that is exactly 1,609.344 metres long. Similarly, 5,280 feet or 1,760 yards make up one mile. The mile is an imperial and common US measurement of distance.

We just have to deal with unit conversions.

One mile is 5280 feet, or  1 ft = 0.000189

The speed of the ball in miles per hour is

\frac{148ft}{1sec} . \frac{1mile}{5280ft} .\frac{60s}{1min} .\frac{60min}{1hr}

So, the speed of the ball in miles per hour is 101miles/hr.

Learn more about miles here;

brainly.com/question/23245414

#SPJ4

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Read 2 more answers
Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms
lakkis [162]

Answer:

(a)  333.77 J

(b) 237.85 J

(c) 4763.77 J

(d) 4667.85 J

Explanation:

Temperature of source, TH = 314 K

Temperature of A, Tc = 292 K

Temperature of B, Tc' = 298 K

heat taken out, Qc = 4430 J

Let the heat deposited outside is QH and QH' by A and B respectively.

\frac{Q_H}{Q_c}=\frac{T_H}{T_c}\\\\Q_H = \frac{4430\times314}{292}=4763.77 J

Now

\frac{Q_H'}{Q_c}=\frac{T_H}{T_c'}\\\\Q_H' = \frac{4430\times314}{298}=4667.85 J

(a) Work done for A

W = QH - QC = 4763.77 - 4430 = 333.77 J

(b) Work done for B

W' = QH' - Qc = 4667.85 - 4430 = 237.85 J

(c) QH = 4763.77 J

(d) QH' = 4667.85 J

4 0
3 years ago
Two ac generators supply the same voltage. However, the first generator has a frequency of 1.2 kHz, and the second has a frequen
astra-53 [7]

Answer:

I_2 = 0.146 A

Explanation:

The formula for current in an inductor is;

I_rms = V_rms/X_L

Where X_L is inductance wirh formula 2πfL

So, I_rms = V_rms/X_L

Applying this to the two generators, we have;

First generator;

I_1 = V_rms/(2π(f_1)L)

And I_2 = V_rms/(2π(f_2)L)

Thus, to find the current in the second generator, we divide eq 1 by eq 2;

So,

I_2/I_1 = [V_rms/(2π(f_2)L)]/[V_rms/(2π(f_1)L)]

Some values will cance out leaving us with;

I_2/I_1 = f_1/f_2

I_2 = I_1(f_1/f_2)

Plugging in the relevant values ;

I_2 = 0.56(1.2/4.6)

I_2 = 0.146 A

6 0
4 years ago
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