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repal postive to postive or negitve to negtive
Answer:
(a) 333.77 J
(b) 237.85 J
(c) 4763.77 J
(d) 4667.85 J
Explanation:
Temperature of source, TH = 314 K
Temperature of A, Tc = 292 K
Temperature of B, Tc' = 298 K
heat taken out, Qc = 4430 J
Let the heat deposited outside is QH and QH' by A and B respectively.

Now

(a) Work done for A
W = QH - QC = 4763.77 - 4430 = 333.77 J
(b) Work done for B
W' = QH' - Qc = 4667.85 - 4430 = 237.85 J
(c) QH = 4763.77 J
(d) QH' = 4667.85 J
Answer:
I_2 = 0.146 A
Explanation:
The formula for current in an inductor is;
I_rms = V_rms/X_L
Where X_L is inductance wirh formula 2πfL
So, I_rms = V_rms/X_L
Applying this to the two generators, we have;
First generator;
I_1 = V_rms/(2π(f_1)L)
And I_2 = V_rms/(2π(f_2)L)
Thus, to find the current in the second generator, we divide eq 1 by eq 2;
So,
I_2/I_1 = [V_rms/(2π(f_2)L)]/[V_rms/(2π(f_1)L)]
Some values will cance out leaving us with;
I_2/I_1 = f_1/f_2
I_2 = I_1(f_1/f_2)
Plugging in the relevant values ;
I_2 = 0.56(1.2/4.6)
I_2 = 0.146 A