To extend the electrical system between the main panel and the secondary panel, the electricians used

A person who weighs 69kg rides with an acceleration of +1.45 m/s2. What is the force exerted by the legs on the person's upper b

trapecia [35]

Answer:

The force exerted by the legs on the person's upper body 32.106 N.

Given:

Mass = 69 kg

Acceleration = 1.45 $\frac{m}{s^{2} }$

To find:

Force exerted by legs on the person's upper body = ?

Formula used:

Force = mass × acceleration

Solution:

Mass of legs = $\frac{32}{100}$ mass of body

Mass of legs = 22.08 kg

According to Newton's second law of motion,

Force = mass × acceleration

Force = 22.08 × 1.45

Force = 32.106 N

The force exerted by the legs on the person's upper body 32.106 N.

4 0

4 years ago

Fe has the electron configuration [Ar]3d64s2. What is the magnitude of the orbital angular momentum for its most energetic elect

salantis [7]

Answer : The magnitude of the orbital angular momentum for its most energetic electron is, $\sqrt{6}\hbar$

Explanation :

The formula used for orbital angular momentum is:

$L=\sqrt{l(l+1)}\hbar$

where,

L = orbital angular momentum

l = Azimuthal quantum number

As we are given the electronic configuration of Fe is, $[Ar]3d^64s^2$

Its most energetic electron will be for 3d electrons.

The value of azimuthal quantum number(l) of d orbital is, 2

That means, l = 2

Now put all the given values in the above formula, we get:

$L=\sqrt{2(2+1)}\hbar$

$L=\sqrt{6}\hbar$

Therefore, the magnitude of the orbital angular momentum for its most energetic electron is, $\sqrt{6}\hbar$

7 0

3 years ago

A rescue team is searching for Andrew, a geologist who was stranded while conducting research in the mountains of Colorado. The

Sindrei [870]

Answer:

I = 9.82 10⁻⁷ W / m²

Explanation:

The intensity of the sound wave is the energy of the wave between the order per unit area of the same

I = P / A = E / T A

the energy is calculated by integrating the mechanical energy in a period, where the mass is changed by the density and ‘s’ is the amplitude of the sound wave

I = ½ ρ v (w s)²

I = ½ 1.35 328 (2π 530 2.00 10⁻⁸)²

I = 221.4 (4.435 10⁻⁹)

I = 9.82 10⁻⁷ W / m²

4 0

4 years ago

Classify the following as either a specific or a nonspecific defense of the body's immune system.

choli [55]

Skin is specific

Macrophages specific

All are specific except fever

3 0

3 years ago

In xray machines, electrons are subjected to electric fields as great as 6.0 x 10^5 N/C. Find

katrin2010 [14]

Answer:

a = 1.055 x 10¹⁷ m/s²

Explanation:

First, we will find the force on electron:

$E = \frac{F}{q}\\\\F = Eq\\$

where,

F = Force = ?

E = Electric Field = 6 x 10⁵ N/C

q = charge on electron = 1.6 x 10⁻¹⁹ C

Therefore,

$F = (6\ x\ 10^5\ N/C)(1.6\ x\ 10^{-19}\ C)\\$

F = 9.6 x 10⁻¹⁴ N

Now, we will calculate the acceleration using Newton's Second Law:

$F = ma\\a = \frac{F}{m}\\$

where,

a = acceleration = ?

m = mass of electron = 9.1 x 10⁻³¹ kg

therefore,

$a = \frac{9.6\ x\ 10^{-14}\ N}{9.1\ x\ 10^{-31}\ kg}\\\\$

5 0

3 years ago