A joule is equivalent to a

A radiographer stands six feet from the x-ray source when performing a portable chest exam and receives an exposure of 2 mGy. If

telo118 [61]

Answer:

I₂ = 8 mG

Explanation:

The intensity of a beam is

I = P / A

Where P is the emitted power which is 3) 3

Let's use index 1 for the initial position of r₁ = 6 ft and 2 for the second position r₂ = 3 ft

I₁ A₁ = I₂ A₂

I₂ = I₁ A₁ / A₂

The area of the beam if we assume that it is distributed either in the form of a sphere is

A₁ = 4π r²

We substitute

I₂ = I₁ (r₁ / r₂)²

I₂ = 2 (6/3)²

I₂ = 2 4

I₂ = 8 mG

3 0

3 years ago

Read 2 more answers

The distance between the ruled lines on a diffraction grating is 1900 nm. The grating is illuminated at normal incidence with a

SashulF [63]

Answer:

3.28 degree

Explanation:

We are given that

Distance between the ruled lines on a diffraction grating, d=1900nm= $1900\times 10^{-9}m$

Where $1nm=10^{-9} m$

$\lambda_2=400nm=400\times10^{-9}m$

$\lambda_1=700nm=700\times 10^{-9}m$

We have to find the angular width of the gap between the first order spectrum and the second order spectrum.

We know that

$\theta=sin^{-1}(\frac{m\lambda}{d})$

Using the formula

m=1

$\theta_1=sin^{-1}(\frac{1\times700\times 10^{-9}}{1900\times 10^{-9}})$

$\theta=21.62^{\circ}$

Now, m=2

$\theta_2=sin^{-1}(\frac{2\times400\times 10^{-9}}{1900\times 10^{-9}})$

$\theta_2=24.90^{\circ}$

$\Delta \theta=\theta_2-\theta_1$

$\Delta \theta=24.90-21.62$

$\Delta \theta=3.28^{\circ}$

Hence, the angular width of the gap between the first order spectrum and the second order spectrum=3.28 degree

6 0

3 years ago

A machinist is required to manufacture a circular metal disk with area 1300 cm2. (a) What radius produces such a disk

vichka [17]

Answer:

Radius r = 20.34 cm

The radius that can produces such a disk is 20.34 cm

Explanation:

Area of a circle;

A = πr^2

A = area

r = radius

Making r the subject of formula;

r = √(A/π) ........1

Given;

A = 1300 cm^2

Substituting into the equation 1;

r = √(1300/π)

r = 20.34214472564 cm

r = 20.34 cm

The radius that can produces such a disk is 20.34 cm

6 0

3 years ago

When throwing curveballs in baseball, is it important to have air hit the ______ part of the ball.

Licemer1 [7]

Answer: A (smooth)

Thanks for using Brainly! You or your parents Vote Biden 2020.

Hope we influence your vote!

7 0

3 years ago

Read 2 more answers

The distance between the centers of the wheels of a motorcycle is 146 cm. The center of mass ofthe motorcycle, including the rid

Vitek1552 [10]

Answer:

9.12267515924 m/s²

Explanation:

Here the moment created by the wheels and the moment created by the center of gravity will balance each other.

h = Height of the center of mass = 78.5 cm

d = Distance from back wheel to the center of mass = $\dfrac{146\times 10^{-2}}{2}\ m$

g = Acceleration due to gravity = 9.81 m/s²

a = Horizontal acceleration

The equation is of the form

$mgd=Fh\\\Rightarrow mgd=mah\\\Rightarrow a=\dfrac{gd}{h}\\\Rightarrow a=\dfrac{9.81\times \dfrac{146\times 10^{-2}}{2}}{78.5\times 10^{-2}}\\\Rightarrow a=9.12267515924\ m/s^2$

The horizontal acceleration of the motorcycle that will make the front wheel rise off the ground is 9.12267515924 m/s²

8 0

3 years ago