Answer:
![n=2.0mol](https://tex.z-dn.net/?f=n%3D2.0mol)
Explanation:
Hello.
In this case, we should use the ideal gas equation in order to compute the the moles of oxygen at the given conditions of 27.0 L, 1.7 atm and 285 K as shown below:
![PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.7atm*27.0L}{0.082\frac{atm*L}{mol*K}*285K}\\ \\n=2.0mol](https://tex.z-dn.net/?f=PV%3DnRT%5C%5C%5C%5Cn%3D%5Cfrac%7BPV%7D%7BRT%7D%3D%5Cfrac%7B1.7atm%2A27.0L%7D%7B0.082%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A285K%7D%5C%5C%20%20%5C%5Cn%3D2.0mol)
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Answer:
Claim: The chemical equation presented in the data table does NOT follow the law of conservation of matter
Evidence: Since we initially have 14.25 grams of Na and 9.5 grams of HCl
we will find the number of moles in each, to further apply stoichiometry
So,
Moles of Na: Given mass/Molar Mass = 14.25/23 = 0.62 Moles of Na
Moles of HCl: Given mass/Molar Mass = 9.5/36.5 = 0.26 Moles of HCl
Since HCl is the limiting reagent in this reaction,
0.26 Moles of Na will be consumed, which is equal to
5.98 grams of Na
Reasoning:
We are given that the total mass of the product is 22.98 grams
but through stoichiometry, we have found that only (9.5 + 5.98) = 15.48 grams of product can possibly be formed
Hence, the reaction presented in the table does NOT follow the law of conservation of matter
<h3>
Answer:</h3>
43.33 atm
<h3>
Explanation:</h3>
We are given;
Mass of C₆H₆ = 26.2 g
Volume of the container = 0.25 L
Temperature = 395 K
We are required to calculate the pressure inside the container;
First, we calculate the number of moles of C₆H₆
Molar mass of C₆H₆ = 78.1118 g/mol.
But; Moles = mass ÷ Molar mass
Moles of C₆H₆ = 26.2 g ÷ 78.1118 g/mol.
= 0.335 moles C₆H₆
Second, we calculate the pressure, using the ideal gas equation;
Using the ideal gas equation, PV = nRT , Where R is the ideal gas constant, 0.082057 L.atm/mol.K
Therefore;
P = nRT ÷ V
= (0.335 mol × 0.082057 × 395 K) ÷ 0.25 L
= 43.433 atm
Therefore, the pressure inside the container is 43.33 atm
Answer: B. 2SO3 + 2SO2 → O2
Hope this helps..... Stay safe and have a Merry Christmas!!!!!! :D