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Hitman42 [59]
3 years ago
15

1. Write the molecular equation, ionic equation, and net ionic equation for the reaction between calcium chloride and ammonium p

hosphate.
Chemistry
1 answer:
aalyn [17]3 years ago
3 0

Answer:

(molecular) 3 CaCl₂(aq) + 2 (NH₄)₃PO₄(aq) ⇄ Ca₃(PO₄)₂(s) +  6 NH₄Cl(aq)

(ionic) 3 Ca²⁺(aq) + 6 Cl⁻(aq) + 6 NH₄⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s) + 6 NH₄⁺(aq) + 6 Cl⁻(aq)

(net ionic) 3 Ca²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s)

Explanation:

The molecular equation includes al the species in the molecular form.

3 CaCl₂(aq) + 2 (NH₄)₃PO₄(aq) ⇄ Ca₃(PO₄)₂(s) +  6 NH₄Cl(aq)

The ionic equation includes all the ions (species that dissociate in water) and the species that do not dissociate in water.

3 Ca²⁺(aq) + 6 Cl⁻(aq) + 6 NH₄⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s) + 6 NH₄⁺(aq) + 6 Cl⁻(aq)

The net ionic equation includes only the ions that participate in the reaction and the species that do not dissociate in water. In does not include <em>spectator ions</em>.

3 Ca²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s)

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For the net reaction: 2AB + 2C → A2 + 2BC, the following slow first steps have been proposed. AB → A + B 2C + AB → AC + BC 2AB →
puteri [66]

This is an incomplete question, here is a complete question.

For the net reaction: 2AB + 2C → A2 + 2BC, the following slow first steps have been proposed.

(1) AB → A + B

(2) 2C + AB → AC + BC

(3) 2AB → A₂ + 2B

(4) C + AB → BC + A

What rate law is predicted by each of these steps?

Answer : The rate law expression for the following reactions are:

(1) \text{Rate}=k[AB]

(2) \text{Rate}=k[C]^2[AB]

(3) \text{Rate}=k[AB]^2

(4) \text{Rate}=k[C][AB]

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The general reaction is:

A+B\rightarrow C+D

The general rate law expression for the reaction is:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

R = rate  law

k = rate constant

[A] and [B] = concentration of A and B reactant

Now we have to determine the rate law for the given reaction.

(1) The balanced equations will be:

AB\rightarrow A+B

In this reaction, AB is the reactant.

The rate law expression for the reaction is:

\text{Rate}=k[AB]

(2) The balanced equations will be:

2C+AB\rightarrow AC+BC

In this reaction, C and AB are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[C]^2[AB]

(3) The balanced equations will be:

2AB\rightarrow A_2+2B

In this reaction, AB is the reactant.

The rate law expression for the reaction is:

\text{Rate}=k[AB]^2

(4) The balanced equations will be:

C+AB\rightarrow BC+A

In this reaction, C and AB are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[C][AB]

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The volume of 7.91 M HCl needed to make 196.1 mL of 2.13 M HCl is ____.
Alona [7]

Answer:

a. 52.8

Explanation:

To find the number of moles of HCl we use the relation M₁V₁=M₂V₂

where M₁ is the initial molarity, M₂ the new molarity, V₁ the initial volume used, and V₂ the final volume obtained.

M₁=7.91 M

M₂=2.13 M

V₁=?

V₂=196.1 mL

Replacing these values in the relationship.

M₁V₁=M₂V₂

7.91 M× V₁=2.13 M×196.1 mL

V₁=(2.13 M×196.1 mL)/7.91 M

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