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kolezko [41]
2 years ago
9

Which situation could be considered pseudoscience?

Physics
2 answers:
sergeinik [125]2 years ago
8 0

Answer:

The second option is the answer.

Explanation:

The students are using beliefs instead of facts or a provable situation.

kap26 [50]2 years ago
7 0

In situation #2, students are gathering to record their beliefs regarding a certain pseudoscientific area of horsefeathers.

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What is the pH of neutral substance?
Lunna [17]

Answer:

7

Explanation:

A substance that is neither acidic nor basic is neutral. The pH scale measures how acidic or basic a substance is. The pH scale ranges from 0 to 14. A pH of 7 is neutral.

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3 years ago
What is the most likely reason it is dangerous to break open a compressed gas tank?
erastova [34]
The main reason why it's very dangerous to open compress gas tank is it can cause major disaster not only in human but also in plants and animals. Compress gas is flammable. And it's like a bomb the damage of gas tank is very catastrophic. It is very harmful if mishandled.
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What the number ??? Help Please
elena55 [62]

Answer:

first number is 113 and the second number is 15

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2 years ago
Suppose a spring has a relaxed length of 28.3 cm. The simulation refers to this as the natural length. This is the length of the
den301095 [7]

Answer:

Explanation:

Normal length of spring = 28.3 cm

stretched length of spring = 38.2 cm

length of extension = 38.2 - 28.3 = 9.9 cm

= 9.9 x 10⁻² m

force applied to stretch = .55 x 9.8 ( mg )

= 5.39 N

Force constant = force applied / extension

= 5.39 / 9.9 x 10⁻²

= .5444 x 10² N /m

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4 0
3 years ago
In odd nuclei, what determines the final spin of the nucleus?
Katen [24]

Answer:

In odd nuclei, the left out proton or neutron will contribute to the spin of the nucleus.

Explanation:

The meaning of odd nuclei is atomic mass is odd.

A=odd number.

A=Z+n

Here, Z is proton either it will odd or n will odd which is neutron.

Now according to the shell model the left out proton or neutron will contribute to the spin and parity.

For example,

Take the case of isotope of nitrogen-15.

Here Z is 7, and n is 8 will not contribute in spin.

Now, for Z=7.

1S^{2} _{\frac{1}{2} }, 1P^{4} _{\frac{3}{2} }, 1P^{1} _{\frac{1}{2} }

Here,

j=\frac{1}{2}

and, L=1.

Fort parity,

(-1)^{L}

Put the value of L.

Parity will be -1.

Now, spin will be

S=(\frac{1}{2} )^{-1}.

7 0
3 years ago
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