When you whirl a can at the end of a string in a circular path, what is the direction of the force that acts on the can
1 answer:
Answer:
Toward the centre of the circular path
Explanation:
The can is moved in a circular path: this means that it is moving by circular motion (uniform circular motion if its tangential speed is constant).
In order to keep a circular motion, an object must have a force that pushes it towards the centre of the circular trajectory: this force is called centripetal force, and its magnitude is given by
where m is the mass of the object, v its tangential speed, r the radius of the trajectory. This force always points towards the centre of the circular path.
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Answer:
The speed of the box at the top of the hill will be 5.693m/s.
Explanation:
The kinetic energy of the box at the bottom of the hill is
putting in and
we get
Now, the potential energy this box gains as it rises up the hill is
Therefore, the energy left in the box at the top if the hill will be
This left-over energy must appear as the kinetic energy of the box at the top of the hill<em> (where else could it go? )</em>; therefore,
putting in numbers and solving for we get:
Thus, the speed of the box at the top of the hill is 5.693m/s.