Hooke's Law says that F=-kx where k is the spring constant measured in N/m (newtons per meter)
D. It is personal in style.
The velocity of the ball when it strikes the ground, given the data is 21.56 m/s
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Time to reach ground from maximum height (t) = 2.2 s
- Initial velocity (u) = 0 m/s
- Acceleration due to gravity (g) = 9.8 m/s²
- Final velocity (v) =?
<h3>How to determine the velocity when the ball strikes the ground</h3>
The velocity of the ball when it strikes the ground can be obtained as illustrated below:
v = u + gt
v = 0 + (9.8 × 2.2)
v = 0 + 21.56
v = 21.56 m/s
Thus, the velocity of the ball when it strikes the ground is 21.56 m/s
Learn more about motion under gravity:
brainly.com/question/22719691
#SPJ1
Answer:
The minimum speed required is 5.7395km/s.
Explanation:
To escape earth, the kinetic energy of the asteroid must be greater or equal to its gravitational potential energy:
or
where 
is the mass of the asteroid, 
is its distance form earth's center, 
is the mass of the earth, and 
is the gravitational constant.
Solving for 
we get:
putting in numerical values gives
in kilometers this is
Hence, the minimum speed required is 5.7395km/s.
Answer: same
Explanation: They both weigh a kilogram and there is no friction
