Question

Calculate the electric force an electron exerts upon a proton inside a He atom if they are d=2.7⋅10^-10m apart.

Answer 1

Explanation:

Charge of electron in He, $q_e=1.6\times 10^{-19}\ kg$

Charge of proton in He, $q_p=1.6\times 10^{-19}\ kg$

Distance between them, $d=2.7\times 10^{-10}\ m$

We need to find the electric force between them. It is given by :

$F=k\dfrac{q_eq_p}{d^2}$

$F=-9\times 10^9\times \dfrac{(1.6\times 10^{-19}\ C)^2}{(2.7\times 10^{-10}\ m)^2}$

$F=-3.16\times 10^{-9}\ N$

Since, there are two protons so, the force become double i.e.

$F=2\times 3.16\times 10^{-9}\ N$

$F=6.32\times 10^{-9}\ N$

So, the correct option is (c). Hence, this is the required solution.