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NemiM [27]
3 years ago
13

LAGOS PROVINCE 10

Physics
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

Explanation:

what?

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Your ear is capable of differentiating sounds that arrive at the ear just 1.00 ms apart. What is the minimum distance (in cm) be
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Answer:

34.3cm

Explanation:

Attached is the full solution

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One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this
Ne4ueva [31]

Answer:

In order to hit the same point with the second ball, you should throw it at an angle of 18° above the horizontal.

Explanation:

Horizontal reach formula for projectiles tells us

d=\frac{v_i^2\sin(2\theta)}{g},

where v_i is the initial velocity and \theta the angle above the horizontal.

Since for both shots the reach must be the same, we have

\frac{v_i^2\sin(2\theta_1)}{g}=\frac{v_i^2\sin(2\theta_2)}{g}\\\sin(2\theta_1)=\sin(2\theta_2)\\\theta_2=\frac{1}{2}\arcsin(\sin(2\theta_1))=\frac{1}{2}\arcsin(\sin(2\times 72\deg))=\mathbf{18\deg}.

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Conclusion of galileo feather and coin experiment
Novosadov [1.4K]

Answer:

This experiment lets you repeat Galileo's experiment in a vacuum. The free fall of a coin and feather are compared, first in a tube full of air and then in a vacuum. With air resistance, the feathers fall more slowly. In a vacuum, the objects fall at the same rate independent of their respective masses.

7 0
3 years ago
Read 2 more answers
The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.0 cm apart with a 20 kV potential
Julli [10]

Answer:

A) electric field strength between the plates;E = 2 x 10^(6) N/C

B) exit velocity;v = 8.39 x 10^(7) m/s

Explanation:

We are given;

Potential difference; V = 20 kV = 20000 V

Distance between the 2 parallel plates; d = 1cm = 0.01 m

A) The electric field strength will be gotten from;

E = V/d

E = 20000/0.01

E = 2000000

E = 2 x 10^(6) N/C

B) For exit speed, we'll use the formula for Kinetic energy; KE = (1/2)mv²

KE is also expressed as; V•q_e

Thus,

(1/2)mv² = V•q_e

Where;

V is potential difference = 20000 V

Q_e is charge of electron which has a constant value of; (1.6 x 10^(-19))C

m is mass of electron with a constant value of (9.1 x 10^(-31)) kg

v is the velocity

Thus, making v the subject, we have;

v = √((2V•q_e)/m)

v = √((2 x 20000•(1.6 x 10^(-19)))/(9.1 x 10^(-31)))

v = 83862786 m/s or

v = 8.39 x 10^(7) m/s

3 0
3 years ago
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