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Marina86 [1]
3 years ago
14

A thin uniform rod of mass M and length L is bent at its center so that the two segments are perpendicular to each other. Find i

ts moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet.
Physics
1 answer:
serg [7]3 years ago
5 0

Answer:

\frac{1}{12}ML^2

Explanation:

The moments of the whole object is the sum of the moments of the 2 segments of rod at their ends of which length is L/2 and mass M/2:

I = 2I_{end} = 2\frac{1}{3}\frac{M}{2}\left(\frac{L}{2}\right)^2

I = \frac{1}{3}M\frac{L^2}{4}

I = \frac{1}{12}ML^2

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