<h3>Answer</h3>
option C)
The wavelength has a length between 7.0 cm and 8.0 cm and the amplitude lies between 1.0 cm and 2.0 cm.
<h3>Explanation</h3><h2>1)</h2>
The amplitude of a wave is the height of a wave as measured from the highest point on the wave, peak, to the rest point or from the lowest point on the wave, trough, to the rest point.
By looking at the image
rest point is at 5cm and crest is at 3.3 cm (y-axis)
so amplitude = 5 - 3.3
= 1.7 cm (approximately)
<h2>2)</h2>
Wavelength refers to the length of a wave from one peak to the next.
one crest is at 2cm and the other crest is at 10cm (x-axis)
so wavelength = 10 - 2
= 8 cm (approximately)
<h3 />
Heat is transferred from the sun-warmed surface of the earth to the cooler overlying troposphere via <u>conduction.</u>
<u />
<h3>Heat transfer from earth to atmosphere:</h3>
Conduction, convection, latent heating, and water phase transitions all help to carry heat from the Earth's surface, which has been warmed by the Sun, to the cooler troposphere above.
Latent heat flux is the worldwide transfer of latent heat energy via water and air currents. Here, we demonstrate how air circulation transports latent heat energy horizontally to cooler regions, where it condenses into rain or is deposited as snow, releasing the heat energy that was previously trapped there.
When air is heated from below by sunshine or by coming into contact with a warmer land or sea surface, convection occurs and the air below becomes less dense than the air above.
Learn more about Latent heat here:
brainly.com/question/12760196
#SPJ4
Answer:
v = 27.456 m/s
Explanation:
The support pressure needed of the water in the straw can be calculated by the formula
Given that,
P = r*g*h
= 1000*9.8*0.05 Pa.= 490 Pa
This pressure is compensated by 0.5*r*v^2 of the air,
Hence,
0.5*1.3*v^2 = 490
velocity of air blown into the straw =
v = 27.456 m/s
Answer:
C) No work is required to move the negative charge from point A to point B.
Explanation:
An equipotential surface is defined as a surface connecting all the points at the same potential.
Therefore, when a charge moves along an equipotential surface, it moves between points at same potential.
The work done when moving a charge is given by
where
q is the charge
is the potential difference between the initial and final point of motion of the charge
However, the charge in this problem moves along an equipotential surface: this means that the potential does not change, so
And so, the work done is also zero.
I am sorry if it didn't helped
answers;
Calculate the buoyant force of a piece of cork of 8cm3 that floats in water. Density of cork is 207kg/m3. ?
I need the mass, in order to get the volume to apply t to the Buoyancy formula of: B=(W)object=(m)object(g)
Explanation:
From Archimedes Principle, any object partially or totally submerged in a fluid is buoyed upwards with a force equal to the weight of the displaced fluid.
∴
B
=
ρ
f
l
V
f
l
g
=
1000
k
g
/
m
3
×
8
×
10
−
6
m
3
×
9
,
8
m
/
s
2
=
0
,
0784
N
(assuming the density of water is at standard temperature and pressure, and that the cork is totally submerged as it floats in the water
it's not the answer of your question ⁉️ but it is similar ........
