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Romashka-Z-Leto [24]
2 years ago
13

A car is moving with a speed of 15

Physics
1 answer:
mars1129 [50]2 years ago
5 0
The unit for the speed was not given

If speed is 15km/h
and distance is 1.2km
Then using the formula
Speed = distance/time
Time = t
15 = 1.2/t
15t = 1.2
t = 1.2/15
t = 0.08hrs

But
1hr = 60seconds
0.08hrs = t
t = 60(0.08)
t = 4.8s
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Answer:

The gazelles top speed is 27.3 m/s.

Explanation:

Given that,

Acceleration = 4.2 m/s²

Time = 6.5 s

Suppose we need to find the gazelles top speed

The speed is equal to the product of acceleration and time.

We need to calculate the gazelles top speed

Using formula of speed

v=at

Where, v = speed

a = acceleration

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Put the value into the formula

v=4.2\times6.5

v=27.3\ m/s

Hence, The gazelles top speed is 27.3 m/s.

6 0
3 years ago
A child whirls a 3.00 kg ball on a string .50 m from the axis of rotation in a horizontal circle. The ball makes 1 revolution in
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Answers:

a) 0.5 m/s^{2}

b) 1.5 N

Explanation:

a) The centripetal acceleration a_{c} of an object moving in a uniform circular motion is given by the following equation:  

a_{c}=\omega^{2} r  

Where:

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r=0.5 m is the radius of the circular motion, which is equal to the length of the string

Then:

a_{c}=(1 \frac{rev}{s})^{2} 0.5 m  

a_{c}=0.5 m/s^{2} This is the centripetal acceleration of the ball

b) On the other hand, in this circular motion there is a force (centripetal force F) that is directed towards the center and is equal to the tension (T) in the string:

F=T=m. a_{c}

Where m=3 kg is the mass of the ball

Hence:

T=(3 kg)(0.5 m/s^{2})

T=1.5 N This is the tension in the string

7 0
3 years ago
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Answer:

0.8214 m/s^2

Explanation:

Fnet= Fpushed - Ffriction

Fpushed = 12.7N      Ffriction = 8.33N

Fnet = 12.7N - 8.33N = 4.37N

Fnet= mass(acceleration)

Fnet = 4.37N    mass = 5.32 kg

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3 years ago
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