A firework is launched with a force of 700 N and a momentum of 200 kg-m/s. How much time before is explodes?
1 answer:
Answer:
t = 0.28 seconds
Explanation:
Given that,
Force acting on a firework, F = 700 N
The momentum of the firework, p =200 kg-m/s
We need to find the time before it explodes. Ket the time be t. We know that, the rate of change of momentum is equal to external frce. So,
So, the required time is equal to 0.28 seconds.
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Answer:
T = 764.41 N
Explanation:
In this case the tension of the string is determined by the centripetal force. The formula to calculate the centripetal force is given by:
(1)
m: mass object = 2.3 kg
r: radius of the circular orbit = 0.034 m
v: tangential speed of the object
However, it is necessary to calculate the velocity v first. To find v you use the formula for the kinetic energy:
You have the value of the kinetic energy (13.0 J), then, you replace the values of K and m, and solve for v^2:
you replace this value of v in the equation (1). Also, you replace the values of r and m:
hence, the tension in the string must be T = Fc = 764.41 N