The work needed to stop the car is
<em>W</em> = ∆<em>K</em> = 0 - 1/2 (1242 kg) (22.5 m/s)² ≈ -314 kJ
A stopping force that does this amount of work, pointing in the opposite direction with magnitude 7210 N, would be exerted over a distance <em>x</em> such that
<em>W</em> = (-7210 N) <em>x</em> ==> <em>x</em> ≈ 43.6 m
Answer:
What is the gravity equation? — It is equal to 6.674×10-11 N·m²/kg². Did you notice that this equation is similar to the formula in Coulomb's law?
Explanation:
Answer:
<h2>0.5 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
From the question we have
We have the final answer as
<h3>0.5 m/s²</h3>
Hope this helps you
Answer:
Explanation:
mass of probe m = 474 Kg
initial speed u = 275 m /s
force acting on it F = 5.6 x 10⁻² N
displacement s = 2.42 x 10⁹ m
A )
initial kinetic energy = 1/2 m u² , m is mass of probe.
= .5 x 474 x 275²
= 17923125 J
B )
work done by engine
= force x displacement
= 5.6 x 10⁻² x 2.42 x 10⁹
= 13.55 x 10⁷ J
C ) Final kinetic energy
= Initial K E + work done by force on it
= 17923125 +13.55 x 10⁷
= 1.79 x 10⁷ + 13.55 x 10⁷
= 15.34 x 10⁷ J
D ) If v be its velocity
1/2 m v² = 15.34 x 10⁷
1/2 x 474 x v² = 15.34 x 10⁷
v² = 64.72 x 10⁴
v = 8.04 x 10² m /s
= 804 m /s
