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3241004551 [841]
3 years ago
10

Lisa is eating dinner.Which sensory organs is she most likely using to process what she is eating?

Physics
2 answers:
Elena-2011 [213]3 years ago
6 0
Tongue, nose, and eyes.
Tongue: to taste what she’s eating
nose: to smell what she’s eating
Eyes: to see what she’s eating.
Sonbull [250]3 years ago
3 0

Answer:

A

Explanation:

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Suppose your local apparent solar time is 11 am, and you have a clock that says it is noon in Greenwich. What is your longitude
jeyben [28]

The longitude based on the time difference is 15 degrees.

<h3>Longitude of complete rotation of the Earth</h3>

The longitude of a complete rotation of the earth in a 24 hours is calculated  as follows;

= \frac{360^0}{24} = 15^0 \ of \ longitude

<h3>Time difference</h3>

The time difference between the local apparent solar time and the Greenwich time is calculated as follows;

t = 12 pm \ - \ 11 am\\\\t = 1 \ hour

Since it is one hour time difference, the longitude is 15 degrees.

Learn more about Earth longitude here: brainly.com/question/1939015

5 0
2 years ago
A machine is currently set to a feed rate of 5.921 inches per minute (IPM). Te machinist changes this setting to 6.088 IPM. By h
lukranit [14]

Answer:

By 16.7% or 0.167 IPM

Explanation:

Substracting the final IPM (6.088) to the initial IPM (5.921) gives us the net difference, which is how much did it increase in IPM. Multiplying this number by 100 gives us the percentual increase in the feed rate.

4 0
3 years ago
Read 2 more answers
A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the magnitude of the dri
nordsb [41]

Complete Question

A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm2.) mm/s

Answer:

The drift velocity is v  = 0.0002808 \ m/s

Explanation:

From the question we are told that

    The current on the copper is  I  = 20 \ A

     The cross-sectional area is  A =  5.261 \ mm^2 =  5.261 *10^{-6} \ m^2

The number of copper atom in the wire is  mathematically evaluated

      n  =  \frac{\rho *  N_a}Z}

Where \rho is the density of copper with a value \rho =  8.93 \ g/m^3

          N_a is the Avogadro's number with a value N_a  = 6.02 *10^{23}\ atom/mol

         Z  is the molar mass of copper with a value  Z =  63.55 \ g/mol

So

     n  =  \frac{8.93 * 6.02 *10^{23}}{63.55}

     n  = 8.46 * 10^{28}  \  atoms /m^3

Given the 1 atom is equivalent to 1 free electron then the number of free electron is  

         N  = 8.46 * 10^{28}  \  electrons

The current through the wire is mathematically represented as

         I  =  N * e * v * A

substituting values

        20 =  8.46 *10^{28} * (1.60*10^{-19}) * v *  5.261 *10^{-6}

=>     v  = 0.0002808 \ m/s

       

8 0
3 years ago
Describe how one plays Dr.Dogeball​
JulsSmile [24]
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Hope this helped! Play on! And plz mark brainliest lol this was long to write :D
4 0
3 years ago
What happens in the process of gravitational condensation?
Lerok [7]

Answer:

An object decreases in size due to the collision of materials. An object increases in size due to the addition of materials. Gas particles are formed from solar nebula materials.

3 0
3 years ago
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