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julia-pushkina [17]
3 years ago
5

When one mole of sodium chloride dissociates in water, it produces: 1 mole of ions ½ mole of sodium ions 2 moles of ions ½ mole

of chloride ions none of these
Chemistry
2 answers:
adelina 88 [10]3 years ago
7 0
Dissociation of NaCl in water is given as below,

                             NaCl ₍s₎    →    Na⁺ ₍aq₎  +  Cl⁻ ₍aq₎

According to this balanced equation the moles on RHS and LHS are as,

Moles on LHS,
                           NaCl ₍s₎   =   1 Mole

Moles on RHS,
                          Na⁺ ₍aq₎   =   1 Mole

                           Cl⁻ ₍aq₎   =    1 Mole
Result:
           
<span>When one mole of sodium chloride dissociates in water, it produces 2 Moles of Ions.</span>
Greeley [361]3 years ago
7 0

Answer: The correct answer is 2 moles of ions. I got this question right on an assignment.

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Select the properly written and balanced equation for the following chemical reaction: Sodium metal and an aqueous solution of m
Setler [38]

Answer:2Na(s)+MgI_2 (aq)\rightarrow 2NaI(aq)+Mg(s)

Explanation: The chemical reaction is written by writing down the chemical formulas of the reactants on the left hand side and the chemical formulas of products on the right hand side separated by a right arrow.

This is a single displacement reaction in which a more reactive element displaces the less reactive element from its salt solution. Thus sodium is more reactive than Mg and thus displaces it from MgI_2.

2Na(s)+MgI_2 (aq)\rightarrow 2NaI(aq)+Mg(s)

The number of atoms of each element must be same on both sides of the reaction so as to follow the law of conservation of mass. Thus the equation is balanced.

5 0
3 years ago
A sample of HI (9.30×10^−3mol) was placed in an empty 2.00 L container at 1000 K. After equilibrium was reached, the concentrati
Sedaia [141]

Answer:

The answer is "29.081"

Explanation:

when the empty 2.00 L container of 1000 kg, a sample of HI (9.30 x 10-3 mol) has also been placed.  

\text{calculating the initial HI}= \frac{mol}{V}

                                       =\frac{9.3 \times 10 ^ -3}{2}

                                      =0.00465 \ Mol

\text{Similarly}\ \  I_2 \ \  \text{follows} \ \  H_2 = 0 }

Its density of I 2 was 6.29x10-4 M if the balance had been obtained, then we have to get the intensity of equilibrium then:

HI  = 0.00465 - 2x\\\\ I_{2}  \ eq = H_2 \ eq = 0 + x \\\\

It is defined that:

I_2 = 6.29 \times 10^{-4}  \ M \\\\x = I_2 \\\\

HI \ eq= 0.00465 - 2x \\

          =0.00465 -2 \times 6.29 \times 10^{-4} \\\\ =  0.00465 -\frac{25.16 }{10^4}  \\\\   = 0.003392\  M

Now, we calculate the position:  

For the reaction H 2(g) + I 2(g)\rightleftharpoons  2HI(g), you can calculate the value of Kc at 1000 K.  

data expression for Kc

2HI \rightleftharpoons  H_2 + I_2 \\\\\to Kc = \frac{H_2 \times I_2}{HI^2}

         = \frac{6.29\times10^{-4} \times 6.29 \times 10^{-4}}{0.003392^2} \\\\= \frac{6.29\times 6.29 \times 10^{-8}}{0.003392^2} \\\\= \frac{39.564 \times 10^{-8}}{1.150 \times 10-5} \\\\= 0.034386

calculating the reverse reaction

H_2(g) + I_2(g)\rightleftharpoons  2HI(g)

Kc = \frac{1}{Kc} \\\\

     = \frac{1}{0.034386}\\ \\= 29.081\\

7 0
3 years ago
Two cars travel next to each other. One speedometer reads
Yanka [14]

Answer:

The pair of arrows which represents the relationship of speeds of the two cars is;

The second option as shown in the attached drawing

Explanation:

The given parameters are;

The reading on the speedometer of one car = 20 m/s

The reading on the speedometer of the other car = 72 km/h = 20 m/s

The blue arrow = 20 m/s

Therefore, given that the speeds of both cars are equal (20 m/s = 72 km/h = 20 m/s),  the pair of arrows that represent the relationship of speeds of the two cars is two equal length blue arrows which is the second option

The attached diagram showing the pair of arrows that represents the relationship of speeds of the two cars is drawn using Microsoft Visio.

4 0
3 years ago
8. Which of the following compounds is an ionic compound? (metal)
fomenos
The answer is b, because all of the other compounds are covelent
6 0
3 years ago
Read 2 more answers
(please, I need some help)
olga55 [171]
c) the salt solubility decreases with temperature.

Salts usually dissolve in water at a given temperature. When water cannot dissolve anymore salt at that same temperature, it is known as a saturation point. With most substances the solubility increases with increase in temperature. Same is the case for a salt like potassium nitrate. With increase in temperature the ability of it to dissolve in water increases. And so with decrease in temperature, the solubility decreases.
7 0
3 years ago
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