Calculate the mols for 4.2g of a Mg
1 answer:
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Answer:
a) Theoretical yield of ethanol = 34.778 g
b) % yield of ethanol = 37.38%
Explanation:
a)
C6H12O6 → 2 C2H5OH + 2 CO2
Molar mass of glucose = 180.156 g/mol
Molar mass of ethanol = 46.07 g/mol
amount of glucose taken = 68.0 g
No. of mole = Amount of substance in g/Molar mass
[text]No. of mole = \frac{68.0\;}{180.156\; g/mol} =0.37745 mol[\text]
from reaction stoichiometry, one mole of glucose fermented two form 2 mole of ethanol.
therefore, 0.37745 mol of glucose will form 0.37745*2 moles of ethanol.
No. of moles of ethanol formed = 0.7549 mol
theoretical yield of ethanol = 0.7549 x 46.07 = 34.778 g
b)
Actual yield = 13.0 g
Theoretical yield = 34.778 g
= 37.38%
Answer : The mass of produced is, 7.74 grams
Solution : Given,
Mass of = 13.3 g
Molar mass of = 227 g/mole
Molar mass of = 44 g/mole
First we have to calculate the moles of .
Now we have to calculate the moles of
The balanced chemical reaction is,
From the reaction, we conclude that
As, 4 mole of react to give 12 mole of
So, 0.0586 moles of react to give
moles of
Now we have to calculate the mass of
Thus, the mass of produced is, 7.74 grams